Home Subjects JEE Physics Magnetism

JEE Physics
Magnetism

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

37 Q 9 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 31–37 of 37
Topics in JEE Physics
Q.31 Easy Magnetism
A magnetic field B is applied perpendicular to a current-carrying wire of length L carrying current I. The magnetic force on the wire is F = BIL sin θ. What is the angle θ when the force is maximum?
A 90°
B 45°
C 180°
D
Correct Answer:  A. 90°
EXPLANATION

Force F = BIL sin θ is maximum when sin θ = 1, which occurs at θ = 90°. This means the wire must be perpendicular to the magnetic field direction.

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Q.32 Easy Magnetism
A moving charge experiences a magnetic force. This force is always:
A Parallel to the velocity
B Perpendicular to both velocity and magnetic field
C In the direction of magnetic field
D Opposite to the velocity
Correct Answer:  B. Perpendicular to both velocity and magnetic field
EXPLANATION

Magnetic force is given by F = q(v × B), which is the cross product of velocity and field. Cross product is always perpendicular to both vectors.

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Q.33 Easy Magnetism
A solenoid of length L, cross-sectional area A, and N turns carries current I. The magnetic field inside the solenoid is:
A B = μ₀NI/L
B B = μ₀LI/N
C B = μ₀N²I/AL
D B = μ₀AI/NL
Correct Answer:  A. B = μ₀NI/L
EXPLANATION

The magnetic field inside a solenoid is uniform and given by B = μ₀nI, where n = N/L is the number of turns per unit length. This is independent of the cross-sectional area A.

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Q.34 Easy Magnetism
The SI unit of magnetic flux density is:
A Weber
B Tesla
C Gauss
D Henry
Correct Answer:  B. Tesla
EXPLANATION

Magnetic flux density (B) is measured in Tesla (T) in SI units. 1 Tesla = 1 Weber/m². Gauss is CGS unit, Weber is unit of flux, and Henry is unit of inductance.

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Q.35 Easy Magnetism
A bar magnet is cut into two equal halves along its length. The magnetic moment of each half is:
A M/2
B M
C 2M
D M/4
Correct Answer:  A. M/2
EXPLANATION

When a bar magnet is cut along its length, each half has half the number of magnetic dipoles. Since magnetic moment is the sum of individual dipole moments, each half has magnetic moment M/2.

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Q.36 Easy Magnetism
The magnetic field at the center of a circular loop of radius R carrying current I is:
A μ₀I/2R
B μ₀I/4πR
C μ₀I/2πR
D μ₀I/πR
Correct Answer:  C. μ₀I/2πR
EXPLANATION

Using Biot-Savart law, the magnetic field at the center of a circular loop of radius R carrying current I is B = μ₀I/2R. This is a fundamental formula in magnetism.

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Q.37 Easy Magnetism
A charged particle moves in a uniform magnetic field perpendicular to its velocity. Which of the following remains constant?
A Kinetic energy of the particle
B Magnetic force on the particle
C Radius of circular path
D Angular velocity of the particle
Correct Answer:  A. Kinetic energy of the particle
EXPLANATION

When a charged particle moves perpendicular to a uniform magnetic field, the magnetic force is always perpendicular to velocity, so it does no work. Hence kinetic energy remains constant. However, direction changes continuously.

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