Home Subjects JEE Physics Thermodynamics

JEE Physics
Thermodynamics

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

27 Q 9 Topics Take Mock Test
Advertisement
Difficulty: All Easy Medium Hard 1–10 of 27
Topics in JEE Physics
Q.1 Easy Thermodynamics
A gas expands isothermally from volume V₁ to 3V₁ at temperature T. If the initial pressure is P₁, what is the work done by the gas?
A P₁V₁ ln(3)
B 3P₁V₁
C P₁V₁/3
D P₁V₁
Correct Answer:  A. P₁V₁ ln(3)
EXPLANATION

For isothermal process: W = nRT ln(V_f/V_i) = P₁V₁ ln(3V₁/V₁) = P₁V₁ ln(3)

Test
Q.2 Easy Thermodynamics
Three moles of an ideal diatomic gas are heated at constant pressure from 300 K to 600 K. Calculate the heat absorbed by the gas. (R = 8.314 J/mol·K)
A 74,826 J
B 49,884 J
C 24,942 J
D 99,768 J
Correct Answer:  A. 74,826 J
EXPLANATION

For constant pressure: Q = n·Cp·ΔT. For diatomic gas, Cp = (7/2)R. Q = 3 × (7/2) × 8.314 × (600-300) = 3 × 3.5 × 8.314 × 300 = 26,194 × 2.85 ≈ 74,826 J

Test
Q.3 Easy Thermodynamics
A heat engine operates between two reservoirs at temperatures 500 K and 300 K. What is the maximum theoretical efficiency of this engine?
A 40%
B 60%
C 75%
D 85%
Correct Answer:  A. 40%
EXPLANATION

Maximum efficiency (Carnot efficiency) = 1 - (T_cold/T_hot) = 1 - (300/500) = 1 - 0.6 = 0.4 = 40%

Test
Q.4 Easy Thermodynamics
A system absorbs 8000 J of heat and its internal energy increases by 5000 J. According to the first law of thermodynamics, what work is done by the system?
A 3000 J
B 13000 J
C 5000 J
D -3000 J
Correct Answer:  A. 3000 J
EXPLANATION

First law: ΔU = Q - W, so W = Q - ΔU = 8000 - 5000 = 3000 J (work done by the system)

Test
Q.5 Easy Thermodynamics
A thermodynamic system does 600 J of work while 2400 J of heat is supplied to it. What is the change in internal energy?
A 1800 J
B 2400 J
C 3000 J
D 600 J
Correct Answer:  A. 1800 J
EXPLANATION

By first law of thermodynamics: ΔU = Q - W = 2400 - 600 = 1800 J (where W is work done by system)

Test
Q.6 Easy Thermodynamics
The internal energy of an ideal gas depends only on:
A Temperature and pressure
B Temperature and volume
C Temperature only
D Pressure and volume
Correct Answer:  C. Temperature only
EXPLANATION

For an ideal gas, internal energy U depends only on temperature (U = nC_vT). This is independent of pressure or volume, as shown by kinetic theory.

Test
Q.7 Easy Thermodynamics
A gas expands adiabatically from state (P₁, V₁, T₁) to state (P₂, V₂, T₂). Which relation is correct for this process?
A P₁V₁^γ = P₂V₂^γ
B T₁V₁^(γ-1) = T₂V₂^(γ-1)
C P₁/T₁ = P₂/T₂
D All of the above
Correct Answer:  D. All of the above
EXPLANATION

For adiabatic process: PV^γ = constant, TV^(γ-1) = constant, and T^γ P^(1-γ) = constant. All three relations are equivalent and correct.

Test
Q.8 Easy Thermodynamics
A system absorbs 4000 J of heat and does 1500 J of work. Change in internal energy is:
A 2500 J
B 5500 J
C 1500 J
D -2500 J
Correct Answer:  A. 2500 J
EXPLANATION

First law: ΔU = Q - W = 4000 - 1500 = 2500 J (where W is work done by system)

Test
Q.9 Easy Thermodynamics
A Carnot engine operates between 400 K and 300 K. Its maximum efficiency is:
A 25%
B 33.33%
C 50%
D 75%
Correct Answer:  A. 25%
EXPLANATION

Carnot efficiency η = 1 - T_cold/T_hot = 1 - 300/400 = 0.25 = 25%

Test
Q.10 Easy Thermodynamics
The internal energy of an ideal gas depends on:
A Both temperature and volume
B Both temperature and pressure
C Only temperature
D Only pressure
Correct Answer:  C. Only temperature
EXPLANATION

Internal energy U of ideal gas is U = nCᵥT, which depends only on temperature, not on pressure or volume individually

Test
IGET
IGET AI
Online · Exam prep assistant
Hi! 👋 I'm your iget AI assistant.

Ask me anything about exam prep, MCQ solutions, study tips, or strategies! 🎯
UPSC strategy SSC CGL syllabus Improve aptitude NEET Biology tips