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JEE Physics
Magnetism

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

44 Q 9 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 41–44 of 44
Topics in JEE Physics
Q.41 Medium Magnetism
The magnetic moment of an electron orbiting in the first Bohr orbit is approximately:
A 1 Bohr magneton
B 0.5 Bohr magneton
C 2 Bohr magneton
D 0.25 Bohr magneton
Correct Answer:  A. 1 Bohr magneton
EXPLANATION

The magnetic moment of an electron in the first Bohr orbit equals 1 Bohr magneton (μ_B = eℏ/2m_e ≈ 9.27 × 10⁻²⁴ J/T). This is a fundamental quantum result.

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Q.42 Medium Magnetism
A rectangular loop of dimensions a × b carrying current I is placed in a uniform magnetic field B. The maximum torque on the loop is:
A τ = BIab
B τ = BIa/b
C τ = BI/ab
D τ = BIa²b
Correct Answer:  A. τ = BIab
EXPLANATION

Torque on a current loop in a magnetic field is τ = NIAB sin(θ), where A is the area and θ is the angle. Maximum torque occurs when sin(θ) = 1, giving τ_max = BIab for N=1.

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Q.43 Medium Magnetism
Two parallel wires carrying currents I₁ and I₂ in opposite directions are separated by distance d. The force between them is:
A Repulsive with magnitude F = μ₀I₁I₂d/2πℓ
B Attractive with magnitude F = μ₀I₁I₂/2πdℓ
C Repulsive with magnitude F = μ₀I₁I₂/2πdℓ
D Attractive with magnitude F = μ₀I₁I₂d/2πℓ
Correct Answer:  C. Repulsive with magnitude F = μ₀I₁I₂/2πdℓ
EXPLANATION

Currents in opposite directions repel each other. The force per unit length is F/ℓ = μ₀I₁I₂/2πd, making total force F = μ₀I₁I₂ℓ/2πd (repulsive).

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Q.44 Medium Magnetism
An electron enters a region of uniform magnetic field with velocity v perpendicular to the field. If the magnetic field strength is B, the radius of curvature is:
A r = mv/eB
B r = eB/mv
C r = m/eBv
D r = eBv/m
Correct Answer:  A. r = mv/eB
EXPLANATION

For a charged particle in a magnetic field, centripetal force equals magnetic force: mv²/r = evB, giving r = mv/eB. This is the radius of the circular path.

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