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JEE Physics
Optics

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

31 Q 9 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 11–20 of 31
Topics in JEE Physics
Q.11 Easy Optics
Which of the following represents the correct relationship for the critical angle θc for total internal reflection?
A sin(θc) = n₂/n₁ where n₁ > n₂
B sin(θc) = n₁/n₂ where n₁ < n₂
C cos(θc) = n₂/n₁ where n₁ > n₂
D tan(θc) = n₂/n₁ where n₁ > n₂
Correct Answer:  A. sin(θc) = n₂/n₁ where n₁ > n₂
EXPLANATION

For total internal reflection from denser to rarer medium, sin(θc) = n₂/n₁ where n₁ is refractive index of denser medium and n₂ of rarer medium

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Q.12 Easy Optics
In Young's double slit experiment, if the distance between slits is doubled while keeping wavelength constant, the fringe width will:
A Become half
B Become double
C Remain unchanged
D Become four times
Correct Answer:  A. Become half
EXPLANATION

Fringe width β = λD/d. If d is doubled, β becomes β/2, i.e., half of the original value

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Q.13 Easy Optics
A light ray travels from medium A (refractive index 1.5) to medium B (refractive index 1.0). If the angle of incidence is 30°, what is the angle of refraction?
A 48.6°
B 45.2°
C 52.4°
D 60.0°
Correct Answer:  A. 48.6°
EXPLANATION

Using Snell's law: n₁sin(θ₁) = n₂sin(θ₂). 1.5 × sin(30°) = 1.0 × sin(θ₂). 1.5 × 0.5 = sin(θ₂). sin(θ₂) = 0.75, θ₂ = 48.6°

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Q.14 Easy Optics
In a laser experiment, the wavelength of light is 632.8 nm. What is the frequency of this light? (Take c = 3 × 10⁸ m/s)
A 4.74 × 10¹⁴ Hz
B 2.37 × 10¹⁴ Hz
C 9.48 × 10¹⁴ Hz
D 4.74 × 10¹⁵ Hz
Correct Answer:  A. 4.74 × 10¹⁴ Hz
EXPLANATION

Frequency f = c/λ = (3 × 10⁸)/(632.8 × 10⁻⁹) = (3 × 10⁸)/(6.328 × 10⁻⁷) ≈ 4.74 × 10¹⁴ Hz.

Test
Q.15 Easy Optics
In a diffraction grating with 5000 lines per cm, what is the grating constant (distance between adjacent slits)?
A 2.0 × 10⁻⁴ cm
B 2.0 × 10⁻⁵ cm
C 5.0 × 10⁻⁴ cm
D 5.0 × 10⁻⁵ cm
Correct Answer:  A. 2.0 × 10⁻⁴ cm
EXPLANATION

Grating constant d = 1/(number of lines per unit length) = 1/5000 cm⁻¹ = 2.0 × 10⁻⁴ cm or 2 μm.

Test
Q.16 Easy Optics
The critical angle for total internal reflection from a denser medium to air (n = 1) is 45°. What is the refractive index of the denser medium?
A 1.41
B 1.50
C 1.73
D 2.00
Correct Answer:  A. 1.41
EXPLANATION

At critical angle: sin(θc) = 1/n. So sin(45°) = 1/n gives 1/√2 = 1/n, therefore n = √2 ≈ 1.41.

Test
Q.17 Easy Optics
A light ray undergoes refraction from medium 1 (n₁ = 1.33) to medium 2 (n₂ = 1.5). If the angle of incidence is 30°, what is the angle of refraction?
A 24.2°
B 27.8°
C 30.0°
D 35.5°
Correct Answer:  B. 27.8°
EXPLANATION

Using Snell's law: n₁sin(θ₁) = n₂sin(θ₂). So 1.33 × sin(30°) = 1.5 × sin(θ₂). Therefore 1.33 × 0.5 = 1.5 × sin(θ₂), which gives sin(θ₂) = 0.443, θ₂ ≈ 27.8°.

Test
Q.18 Easy Optics
In Young's double slit experiment, the distance between slits is 0.5 mm, distance to screen is 1 m, and wavelength is 500 nm. What is the fringe width?
A 0.5 mm
B 1.0 mm
C 2.0 mm
D 4.0 mm
Correct Answer:  B. 1.0 mm
EXPLANATION

Fringe width β = λD/d = (500 × 10⁻⁹ × 1)/(0.5 × 10⁻³) = 500 × 10⁻⁶/0.5 × 10⁻³ = 1.0 mm.

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Q.19 Easy Optics
A concave lens of focal length 20 cm forms an image at a distance of 10 cm from the lens. At what distance from the lens should the object be placed?
A 15 cm
B 20 cm
C 30 cm
D 40 cm
Correct Answer:  B. 20 cm
EXPLANATION

Using lens formula: 1/f = 1/v + 1/u. For concave lens, f = -20 cm, v = -10 cm (virtual image). So 1/-20 = 1/-10 + 1/u gives 1/u = -1/20 + 1/10 = 1/20, therefore u = 20 cm.

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Q.20 Easy Optics
A plane mirror is moved towards a stationary object at a distance of 10 cm from the mirror. What is the velocity of the image if the mirror moves with a velocity of 2 m/s towards the object?
A 4 m/s towards the object
B 2 m/s towards the object
C 1 m/s towards the object
D 8 m/s towards the object
Correct Answer:  A. 4 m/s towards the object
EXPLANATION

When a plane mirror moves towards an object with velocity v, the image also moves towards the mirror with velocity v. The relative velocity of approach between object and image is 2v. Therefore, velocity of image = 2 × 2 = 4 m/s.

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