Govt. Exams
Entrance Exams
For constructive interference, A_resultant = A₁ + A₂ = 3 + 4 = 7 units
n = c/v = (3×10⁸)/(2×10⁸) = 1.5
Using v = fλ, we get λ = v/f = 20/50 = 0.4 m
Energy E ∝ A² for harmonic waves. Kinetic energy = (1/2)mω²A²sin²(ωt)
At nodes, particles do not move. Amplitude of oscillation is zero, hence particle velocity is always zero
For a point source, intensity spreads over a sphere of area 4πr², so I ∝ 1/r²
λ = v/f = 330/440 = 0.75 m
From y = Asin(ωt - kx), ω = 2π/0.04 = 50π, k = 2π/0.8 = 2.5π. v = ω/k = 50π/2.5π = 20 m/s
Beat frequency = |f₁ - f₂| = |256 - 260| = 4 Hz
Using v = fλ, we get λ = v/f = 20/50 = 0.4 m