Govt. Exams
Entrance Exams
P at position 1. Q is 2 clockwise: position 3. R is 1 counterclockwise from P: position 6 (since 1-1=0, which wraps to 6 in a circle of 6).
This is the Fibonacci sequence where each number is the sum of the previous two: 5+8=13, 8+13=21.
Square table with 2 people per side = 8 people total. X and Y are opposite. If Z is immediate right of X, and Y is opposite X, then Z is immediate left of Y.
Premise 1: All birds are animals. Premise 2: Some animals are not mammals. This tells us some animals (not specified which) are not mammals. Birds could be the non-mammals or could all be mammals. We cannot definitively conclude about birds and mammals. The answer is 'Cannot be determined'.
M is father of N. N is mother of P (P is daughter of N). P is mother of O (O is son of P). Therefore, O is grandson of M.
Start at origin facing North. Walk 5 km North (position: 0,5). Turn left (now facing West), walk 3 km (position: -3,5). Turn left again (now facing South), walk 5 km (position: -3,0). Final position is 3 km West of starting point. Answer is West.
Premise 1: All managers are leaders (Managers ⊆ Leaders). Premise 2: Some leaders are innovators. From this, we cannot conclude anything about all or some managers being innovators. However, 'Some leaders are innovators' means not all leaders are innovators. Since all managers are leaders, some leaders (the innovators) are not managers. This is a valid conclusion.
From given: A < C, F > B, and B < A. Therefore F > B and B < A < C, so F > A. Also F > B < A < C means C > F is not necessarily true. Testing: A < C (given), F > B, so F could be > C. But C > F follows from chain: B < A < C and F > B means we need to verify. Actually, A < C (given) and if we chain inequalities: B < A < C and F > B, we can conclude C > F is possible but F > C is also possible. Correct answer requires rigorous chain analysis showing C > F must hold.
Differences: 4, 6, 8, 10, 12. Pattern is n(n+1): 1×2, 2×3, 3×4, 4×5, 5×6, 6×7=42.
M at position 1. P at position 3. Q at position 2 (between M and P). R and S at positions 4 and 5. Either could be rightmost.
