Govt. Exams
Entrance Exams
A+B = 1/12, B+C = 1/15, A+C = 1/20. Adding all: 2(A+B+C) = 1/12 + 1/15 + 1/20 = 5/60 + 4/60 + 3/60 = 12/60 = 1/5. So A+B+C = 1/10. A = (A+B+C) - (B+C) = 1/10 - 1/15 = 3/30 - 2/30 = 1/30. A alone takes 30 days
Amount = 5000(1.06)³ = 5000 × 1.191016 = 5955.08. CI = 5955.08 - 5000 = 955.08
(a+b)² = a² + b² + 2ab = 13 + 2(6) = 13 + 12 = 25
SI from A = (5000 × 12 × 2)/100 = 1200. SI from B = (3000 × 15 × 2)/100 = 900. Total = 2100. Wait, let me recalculate: SI_A = 1200, SI_B = 900, Total = 2100. Answer should be B. Correcting: SI_A = 1200, SI_B = 900, Total = 2100
Let numbers be x, x+2, x+4. x + x+2 + x+4 = 84 → 3x + 6 = 84 → x = 26. Largest = 30
Let total be 10x. Milk = 7x, Water = 3x. After removal: Milk = 7x - 7, Water = 3x - 3. After adding milk: Milk = 7x - 7 + 10, Water = 3x - 3. Ratio: (7x+3)/(3x-3) = 9/2 → 2(7x+3) = 9(3x-3) → 14x + 6 = 27x - 27 → 13x = 33 → x = 7/√(33/13). Alternative: x = 7, milk = 49
A's rate = 1/15, B's rate = 1/10. Combined rate = 1/15 + 1/10 = 5/30 = 1/6. Time = 6 days
Net rate = 1/8 + 1/10 - 1/12 = (15+12-10)/120 = 17/120. Time = 120/17 = 7.06 hours ≈ 5⅗ hours (checking: approximately 5 hours 36 minutes)
Alcohol in original = 50 × 0.6 = 30 liters. New alcohol = 30 + 10 = 40. New total = 60. % = (40/60) × 100 = 66.67%