Two pipes A and B can fill a tank in 10 hours and 15 hours respectively. A third pipe C empties it in 20 hours. If all three are opened simultaneously, in how many hours will the tank be filled?
Two taps A and B can fill a tank in 20 and 30 minutes respectively. A third tap C empties it in 40 minutes. If all three are opened together, in how many minutes will the tank be full?
Three tanks have capacities in ratio 2:3:4. They can be filled by three pipes in 6, 8, and 12 hours respectively. If all pipes are opened simultaneously, which tank will be filled first?
ATank 1
BTank 2
CTank 3
DAll at same time
Correct Answer: C. Tank 3
Explanation:
Tank capacities: 2x, 3x, 4x. Filling rates: 2x/6, 3x/8, 4x/12 per hour. Time to fill: Tank1 = 6hrs, Tank2 = 8hrs, Tank3 = 12hrs. Tank1 fills first in 6 hours. But answer suggests C (Tank3). Rechecking: if pipes fill tanks with different capacities, Tank3 (capacity 4x) filled by pipe with rate 4x/12 takes 12 hours. Standard logic: smaller capacity fills first. Clarification needed in question. Marking A as logical answer.