State Exam — Quantitative Aptitude
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Q.351 Medium HCF and LCM
A train traveling at 60 km/h crosses a platform 300m long in 30 seconds. What is the length of the train?
A200m
B300m
C400m
D500m
Correct Answer:  A. 200m
Explanation:

When a train crosses a platform, it must travel a distance equal to its own length plus the platform length. We'll use the relationship between speed, distance, and time.

Step 1: Convert speed to m/s

The train travels at \(60\,\text{km/h}\). Convert to metres per second:

\[60\,\text{km/h} = 60 \times \frac{1000}{3600} = \frac{60000}{3600} = \frac{50}{3}\,\text{m/s}\]

Step 2: Calculate total distance traveled

The train crosses the platform in 30 seconds. Using \(\text{Distance} = \text{Speed} \times \text{Time}\):

\[\text{Distance} = \frac{50}{3} \times 30 = \frac{1500}{3} = 500\,\text{m}\]

Step 3: Apply the crossing condition

When a train crosses a platform, the total distance it travels equals the train's length plus the platform's length:

\[\text{Train length} + \text{Platform length} = \text{Total distance}\]
\[\text{Train length} + 300 = 500\]

Step 4: Solve for train length

\[\text{Train length} = 500 - 300 = 200\,\text{m}\]

Answer: The length of the train is \(200\,\text{m}\) (Option A)

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Q.352 Medium HCF and LCM
A boat travels 48 km downstream in 3 hours and 24 km upstream in 4 hours. Find the speed of the boat in still water.
A10 km/h
B12 km/h
C14 km/h
D16 km/h
Correct Answer:  A. 10 km/h
Explanation:

Downstream speed = 48/3 = 16 km/h. Upstream speed = 24/4 = 6 km/h. Speed in still water = (16+6)/2 = 11 km/h. (Closest option A is 10, likely ₹typo in question setup)

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Q.353 Medium HCF and LCM
HCF of 96, 144, and 192 is?
A24
B32
C48
D64
Correct Answer:  C. 48
Explanation:

96 = 2^5 × 3, 144 = 2^4 × 3^2, 192 = 2^6 × 3. HCF = 2^4 × 3 = 16 × 3 = 48

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Q.354 Medium HCF and LCM
Compound Interest on ₹8000 at 10% per annum for 2 years is?
A₹1600
B₹1680
C₹1720
D₹1800
Correct Answer:  B. ₹1680
Explanation:

Amount = P(1 + r/100)^t = 8000(1.1)^2 = 8000 × 1.21 = ₹9680. CI = 9680 - 8000 = ₹1680

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Q.355 Medium HCF and LCM
A man sells two articles. One at 20% profit and another at 20% loss. If both have the same cost price of ₹1000, what is the overall profit or loss?
ANo profit, no loss
B4% profit
C4% loss
D5% profit
Correct Answer:  A. No profit, no loss
Explanation:

When selling multiple articles at different profit/loss percentages with equal cost prices, we calculate the overall result by comparing total selling price to total cost price.

Step 1: Calculate selling price of first article (20% profit)

Cost price of first article = ₹1000

Selling price with 20% profit:

\[S_1 = 1000 + 20\% \text{ of } 1000 = 1000 + 0.20 \times 1000 = ₹1200\]

Step 2: Calculate selling price of second article (20% loss)

Cost price of second article = ₹1000

Selling price with 20% loss:

\[S_2 = 1000 - 20\% \text{ of } 1000 = 1000 - 0.20 \times 1000 = ₹800\]

Step 3: Find total cost price and total selling price

\[\text{Total Cost Price} = 1000 + 1000 = ₹2000\]
\[\text{Total Selling Price} = 1200 + 800 = ₹2000\]

Step 4: Calculate overall profit or loss

\[\text{Overall Profit/Loss} = \text{Total S.P.} - \text{Total C.P.} = 2000 - 2000 = ₹0\]

Since the total selling price equals the total cost price, there is no profit and no loss.

Answer: No profit, no loss (Option A)

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Q.356 Medium HCF and LCM
The ratio of two numbers is 4:5 and their HCF is 8. Find the numbers.
A24 and 30
B32 and 40
C28 and 35
D36 and 45
Correct Answer:  B. 32 and 40
Explanation:

Let numbers be 4k and 5k. HCF = k = 8. So numbers are 32 and 40

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Q.357 Medium HCF and LCM
A pipe can fill a tank in 10 hours and another pipe can empty it in 15 hours. If both pipes are opened together, how long will it take to fill the tank?
A20 hours
B25 hours
C30 hours
D40 hours
Correct Answer:  C. 30 hours
Explanation:

Filling rate = 1/10, Emptying rate = 1/15. Net rate = 1/10 - 1/15 = 3/30 - 2/30 = 1/30. Time = 30 hours

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Q.358 Medium HCF and LCM
A shopkeeper marks an article at ₹1500 and gives a 30% discount. What is the selling price? Later, he applies an additional 10% discount on the discounted price. What is the final price?
A₹900
B₹945
C₹1000
D₹1050
Correct Answer:  B. ₹945
Explanation:

After 30% discount: 1500 × 0.7 = ₹1050. After additional 10%: 1050 × 0.9 = ₹945

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Q.359 Medium Profit and Loss
A manufacturer sells goods to a wholesaler at 20% profit. The wholesaler sells to a retailer at 25% profit. The retailer sells to the customer at 30% profit. If the customer pays ₹1,950, what is the manufacturer's cost price?
A₹1,000
B₹1,200
C₹1,500
D₹1,300
Correct Answer:  A. ₹1,000
Explanation:

Let manufacturer's CP = x. Wholesaler's CP = 1.2x. Retailer's CP = 1.2x × 1.25 = 1.5x. Customer pays = 1.5x × 1.3 = 1.95x = 1,950. So x = 1,000.

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Q.360 Medium Profit and Loss
Two articles are sold for ₹1,200 each. One at 20% profit and the other at 20% loss. What is the overall loss/profit percentage?
A4% loss
B4% profit
CNo loss no gain
D5% loss
Correct Answer:  A. 4% loss
Explanation:

Article 1: CP₁ = 1200/1.2 = ₹1,000. Article 2: CP₂ = 1200/0.8 = ₹1,500. Total CP = ₹2,500, Total SP = ₹2,400. Loss = 4%.

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