Govt. Exams
Entrance Exams
Using v² = u² - 2as, where v = 0, u = 20 m/s, a = 5 m/s². Therefore, s = u²/(2a) = 400/10 = 40 m
Impulse = Δ(momentum) = m(v₂ - v₁) = 5(10 - 4) = 30 N·s
Total mass = m + 2m + 3m = 6m. Using F = Ma: a = F/(6m)
v = ωr = 10 × 0.2 = 2 m/s
Efficiency = (Work output/Work input) × 100. 80 = (8000/W) × 100 → W = 10000 J
Friction is f = μN where μ depends on surface nature and N is normal force. Static friction can be equal to or less than maximum static friction.
Range R = u²sin(2θ)/g = (40)²sin(90°)/10 = 1600/10 = 160 m
Centripetal acceleration ac = v²/r = (20)²/50 = 400/50 = 8 m/s²
Centripetal acceleration always points toward center of circle (radially inward), perpendicular to velocity
Newton's first law: uniform velocity means acceleration = 0, hence net force = 0