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JEE Physics
Semiconductors

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

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Difficulty: All Easy Medium Hard 31–40 of 50
Topics in JEE Physics
Q.31 Medium Semiconductors
In a solar cell, the maximum power output occurs when the operating point satisfies which condition?
A Voltage = open circuit voltage (Voc)
B Current = short circuit current (Isc)
C Power (V×I) is maximum at knee of I-V curve
D Forward bias voltage equals bandgap energy
Correct Answer:  C. Power (V×I) is maximum at knee of I-V curve
EXPLANATION

Maximum power point (MPP) occurs at the knee of the I-V characteristic where the product V×I is maximum, typically at ~80% of Voc and ~90% of Isc.

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Q.32 Medium Semiconductors
A photodiode operates in reverse bias to:
A Increase the bandgap energy
B Widen the depletion region for better light collection
C Decrease the junction capacitance
D Increase the forward current
Correct Answer:  B. Widen the depletion region for better light collection
EXPLANATION

Reverse bias widens the depletion region, allowing photogenerated carriers throughout this region to be swept out by the electric field, improving collection efficiency and response time.

Test
Q.33 Medium Semiconductors
In an n-channel JFET (Junction Field Effect Transistor), when the gate-source voltage (Vgs) becomes more negative, what happens to the channel conductance?
A Conductance increases
B Conductance decreases due to depletion region expansion
C Conductance remains constant
D Channel gets inverted to p-type
Correct Answer:  B. Conductance decreases due to depletion region expansion
EXPLANATION

More negative Vgs increases the reverse bias on the gate junction, expanding the depletion region and narrowing the conducting channel, thus decreasing conductance.

Test
Q.34 Medium Semiconductors
The minority carrier diffusion length Ln in a semiconductor depends on which parameters?
A Only on bandgap energy Eg
B On diffusion coefficient Dn and minority carrier lifetime τn
C Only on doping concentration
D On applied external voltage only
Correct Answer:  B. On diffusion coefficient Dn and minority carrier lifetime τn
EXPLANATION

Diffusion length Ln = √(Dn·τn) where Dn is diffusion coefficient and τn is minority carrier lifetime. It represents the average distance a carrier travels before recombination.

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Q.35 Medium Semiconductors
A compound semiconductor like GaAs has a direct bandgap while Si has an indirect bandgap. Which statement about light emission is correct?
A Both emit light with equal efficiency under forward bias
B GaAs is more suitable for LEDs due to direct bandgap allowing direct recombination
C Si emits more light than GaAs due to higher Eg
D Indirect bandgap materials are better for light emission
Correct Answer:  B. GaAs is more suitable for LEDs due to direct bandgap allowing direct recombination
EXPLANATION

Direct bandgap semiconductors like GaAs allow radiative recombination (photon emission) without phonon assistance, making them ideal for LEDs and lasers.

Test
Q.36 Medium Semiconductors
In a Zener diode, the Zener breakdown occurs due to:
A Impact ionization of carriers
B Tunneling of electrons from valence band to conduction band
C Thermal generation of carriers
D Forward biasing of the junction
Correct Answer:  B. Tunneling of electrons from valence band to conduction band
EXPLANATION

Zener breakdown (sharp, reversible breakdown at lower voltages) occurs when a strong electric field in the depletion region enables direct tunneling of electrons across the narrow bandgap.

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Q.37 Medium Semiconductors
The reverse saturation current (I₀) in a p-n junction increases exponentially with temperature. This is primarily because:
A Thermal generation of minority carriers increases
B Depletion width decreases
C Junction capacitance increases
D Applied reverse bias increases
Correct Answer:  A. Thermal generation of minority carriers increases
EXPLANATION

I₀ ∝ ni² which increases exponentially with temperature. This thermal generation of minority carriers in the neutral regions near the junction constitutes the reverse saturation current.

Test
Q.38 Medium Semiconductors
A silicon semiconductor has ni = 1.5 × 10^10 cm^-3 at 300K. If doped with 10^16 cm^-3 donor atoms, calculate the hole concentration at thermal equilibrium.
A 1.5 × 10^10 cm^-3
B 2.25 × 10^4 cm^-3
C 10^16 cm^-3
D 1.5 × 10^26 cm^-3
Correct Answer:  B. 2.25 × 10^4 cm^-3
EXPLANATION

Using mass action law: ne·nh = ni². Since ne ≈ Nd = 10^16 cm^-3, then nh = ni²/ne = (1.5×10^10)²/10^16 = 2.25×10^4 cm^-3

Test
Q.39 Medium Semiconductors
In a reverse-biased p-n junction, the depletion width increases when:
A Forward bias voltage is increased
B Reverse bias voltage magnitude is increased
C Temperature is increased
D Doping concentration is decreased uniformly
Correct Answer:  B. Reverse bias voltage magnitude is increased
EXPLANATION

Increasing reverse bias voltage creates a stronger electric field, pushing charge carriers away from the junction and widening the depletion region according to W ∝ √V.

Test
Q.40 Medium Semiconductors
The conductivity of a semiconductor is given by σ = e(neμe + nhμh). If temperature increases from 300K to 400K, which factor primarily determines the change in conductivity?
A Increase in carrier concentration dominates
B Decrease in mobility dominates
C Both effects cancel each other
D Bandgap energy becomes zero
Correct Answer:  A. Increase in carrier concentration dominates
EXPLANATION

Though mobility decreases with temperature (T^-3/2), the exponential increase in carrier concentration (proportional to exp(-Eg/2kT)) dominates, resulting in net increase in conductivity.

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