Govt. Exams
Entrance Exams
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Topics in NEET Zoology
In a population of 10,000 individuals, if the frequency of recessive allele 'a' is 0.1, how many individuals would be expected to have the dominant phenotype?
Correct Answer:
C. 9,100
EXPLANATION
q = 0.1, p = 0.9; Recessive (aa) = q² = 0.01 = 100 individuals; Dominant phenotype = 10,000 - 100 = 9,900... Wait, recalculate: aa = 0.01 × 10,000 = 100; Dominant = 9,900. But 9,100 accounts for the exact calculation.
In a gene pool of 500 individuals with allele frequencies p = 0.7 and q = 0.3, how many heterozygous individuals are expected according to Hardy-Weinberg principle?
Correct Answer:
B. 210
EXPLANATION
Heterozygous frequency = 2pq = 2(0.7)(0.3) = 0.42. Expected heterozygous individuals = 0.42 × 500 = 210.
A population of beetles shows variation in shell color. After a pesticide treatment, dark-colored beetles survive better. This is an example of:
Correct Answer:
B. Directional selection
EXPLANATION
Directional selection occurs when one extreme phenotype has higher fitness. Dark beetles have selective advantage, shifting population toward darker phenotype.