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Chemical Engineering
Thermodynamics

Process design, thermodynamics, reactions

49 Q 5 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 1–10 of 49
Topics in Chemical Engineering
Q.1 Medium Thermodynamics
A reversible process between two states A and B will have entropy change:
A Greater than that of an irreversible process between same states
B Less than that of an irreversible process between same states
C Equal to that of any path between same states
D Dependent on the type of process
Correct Answer:  C. Equal to that of any path between same states
EXPLANATION

Entropy is a state function. ΔS is path-independent and same for all processes (reversible or irreversible) between fixed states.

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Q.2 Medium Thermodynamics
For a constant pressure process, the heat absorbed equals:
A Change in internal energy
B Change in enthalpy
C Change in entropy
D Work done by system
Correct Answer:  B. Change in enthalpy
EXPLANATION

At constant pressure: ΔH = Q_p (definition of enthalpy). From ΔU = Q - W and W = PΔV, we get Q = ΔH.

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Q.3 Medium Thermodynamics
The compressibility factor Z for a real gas at high pressures is typically:
A Greater than 1 (repulsive forces dominate)
B Less than 1 (attractive forces dominate)
C Equal to 1
D Always greater than 2
Correct Answer:  A. Greater than 1 (repulsive forces dominate)
EXPLANATION

At high pressures, molecular volume effect (b term) dominates, making Z > 1. At moderate pressures, Z < 1 due to intermolecular attractions.

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Q.4 Medium Thermodynamics
For a binary ideal solution, Raoult's law states that:
A Partial pressure of each component = mole fraction × vapor pressure of pure component
B Total pressure = sum of mole fractions × atmospheric pressure
C Activity coefficient of each component = 1
D Vapor pressure is independent of composition
Correct Answer:  A. Partial pressure of each component = mole fraction × vapor pressure of pure component
EXPLANATION

Raoult's law: P_i = x_i × P_i° for ideal solutions. Both statements A and C are equivalent for ideal solutions.

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Q.5 Medium Thermodynamics
The Joule-Thomson coefficient μ_JT is negative for most gases at room temperature. This means:
A Temperature increases during expansion
B Temperature decreases during expansion
C No temperature change occurs
D Entropy decreases during expansion
Correct Answer:  A. Temperature increases during expansion
EXPLANATION

μ_JT = (∂T/∂P)_H. Negative coefficient means T increases with pressure drop (cooling requires very low T or high P).

Test
Q.6 Medium Thermodynamics
In an adiabatic compression process for an ideal gas, which statement is correct?
A Temperature remains constant
B Work done equals change in internal energy
C Entropy increases
D Heat capacity is zero
Correct Answer:  B. Work done equals change in internal energy
EXPLANATION

For adiabatic process, Q = 0, so ΔU = W (first law). Temperature increases during compression.

Test
Q.7 Medium Thermodynamics
The Maxwell relation derived from dG = -SdT + VdP is:
A (∂S/∂P)_T = (∂V/∂T)_P
B (∂S/∂P)_T = -(∂V/∂T)_P
C (∂S/∂T)_P = (∂V/∂P)_T
D (∂V/∂T)_P = (∂P/∂S)_V
Correct Answer:  B. (∂S/∂P)_T = -(∂V/∂T)_P
EXPLANATION

From dG = -SdT + VdP, cross derivatives give (∂S/∂P)_T = -(∂V/∂T)_P, a Maxwell relation.

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Q.8 Medium Thermodynamics
For a spontaneous adiabatic process in an isolated system, entropy must:
A Decrease
B Remain constant
C Increase or remain constant
D Equal zero
Correct Answer:  C. Increase or remain constant
EXPLANATION

Second law: dS_universe ≥ 0. For isolated systems, dS_system ≥ 0. Equality holds for reversible adiabatic processes.

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Q.9 Medium Thermodynamics
In a throttling process (Joule-Thomson expansion), which property remains constant?
A Temperature
B Enthalpy
C Entropy
D Internal energy
Correct Answer:  B. Enthalpy
EXPLANATION

Throttling through a valve occurs at constant enthalpy (isenthalpic process). This explains cooling of real gases during expansion.

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Q.10 Medium Thermodynamics
The work done by a system during expansion against constant external pressure P_ext is:
A W = nRT ln(V_f/V_i)
B W = P_ext(V_f - V_i)
C W = ∫P_int dV
D W = ΔH - TΔS
Correct Answer:  B. W = P_ext(V_f - V_i)
EXPLANATION

For constant external pressure, work is W = P_ext × ΔV. This is path-dependent work for irreversible processes.

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