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Chemical Engineering
Thermodynamics

Process design, thermodynamics, reactions

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Difficulty: All Easy Medium Hard 41–49 of 49
Topics in Chemical Engineering
Q.41 Medium Thermodynamics
For a spontaneous process at constant T and P, which condition must be satisfied?
A ΔH < 0 always
B ΔS > 0 always
C ΔG < 0
D ΔU < 0
Correct Answer:  C. ΔG < 0
EXPLANATION

At constant T and P, spontaneity is determined by Gibbs free energy: ΔG < 0 for spontaneous process, ΔG = 0 for equilibrium, ΔG > 0 for non-spontaneous process.

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Q.42 Medium Thermodynamics
For a real gas with van der Waals equation, the constants 'a' and 'b' represent:
A a = molecular volume, b = intermolecular attraction
B a = intermolecular attraction, b = molecular volume
C a = pressure correction, b = temperature correction
D a = temperature effect, b = composition effect
Correct Answer:  B. a = intermolecular attraction, b = molecular volume
EXPLANATION

In van der Waals equation (P + a/V²)(V - b) = RT, 'a' accounts for intermolecular attractive forces and 'b' represents excluded molecular volume. Both are positive constants.

Test
Q.43 Medium Thermodynamics
The heat capacity at constant pressure Cₚ is always greater than heat capacity at constant volume Cᵥ because:
A At constant V, no expansion work is done
B At constant P, additional heat is needed for expansion work
C Pressure affects the molecular motion more at constant P
D Volume has less effect on internal energy than pressure
Correct Answer:  B. At constant P, additional heat is needed for expansion work
EXPLANATION

Cₚ - Cᵥ = R (for ideal gas). At constant P, supplied heat does both internal energy and expansion work. At constant V, all heat goes to internal energy only.

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Q.44 Medium Thermodynamics
A cyclic heat engine operates between hot reservoir at 500 K and cold reservoir at 300 K. Maximum theoretical efficiency is:
A 60%
B 40%
C 50%
D 80%
Correct Answer:  B. 40%
EXPLANATION

Maximum efficiency is Carnot efficiency: η_max = 1 - T_cold/T_hot = 1 - 300/500 = 0.40 = 40%. No heat engine can exceed this efficiency.

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Q.45 Medium Thermodynamics
For a reversible process, the Clausius inequality states:
A ΔS > Q/T
B ΔS = Q_rev/T
C ΔS < Q/T
D ΔS ≥ Q_rev/T always
Correct Answer:  B. ΔS = Q_rev/T
EXPLANATION

For reversible processes, ΔS = Q_rev/T. For irreversible processes, ΔS > Q_irrev/T. This is the Clausius inequality: dS ≥ dQ/T.

Test
Q.46 Medium Thermodynamics
The heat of vaporization of water is 40.66 kJ/mol at 373 K. The entropy of vaporization is approximately:
A 0.109 kJ/mol·K
B 0.109 J/mol·K
C 109 J/mol·K
D 218 J/mol·K
Correct Answer:  C. 109 J/mol·K
EXPLANATION

ΔS_vap = ΔH_vap/T = 40660 J/mol / 373 K ≈ 109 J/mol·K. This follows Trouton's rule (~85-105 J/mol·K for most liquids).

Test
Q.47 Medium Thermodynamics
For a process where ΔG < 0 at all temperatures, the process must be:
A Endothermic with ΔS < 0
B Exothermic with ΔS > 0
C Exothermic with ΔS < 0
D Endothermic with ΔS > 0
Correct Answer:  B. Exothermic with ΔS > 0
EXPLANATION

From ΔG = ΔH - TΔS, for ΔG < 0 at all T: ΔH < 0 (exothermic) and ΔS > 0 (entropy increases). This is a spontaneous process at all temperatures.

Test
Q.48 Medium Thermodynamics
For an ideal gas undergoing isothermal expansion, the work done is given by:
A W = nRTln(V₂/V₁)
B W = nCᵥΔT
C W = PΔV
D W = nCₚΔT
Correct Answer:  A. W = nRTln(V₂/V₁)
EXPLANATION

For isothermal process of ideal gas, W = nRTln(V₂/V₁) = nRTln(P₁/P₂). This is derived from the first law with ΔU = 0 for isothermal ideal gas process.

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Q.49 Medium Thermodynamics
Which thermodynamic potential is most useful for constant temperature and pressure processes?
A Internal Energy (U)
B Helmholtz Free Energy (F)
C Gibbs Free Energy (G)
D Enthalpy (H)
Correct Answer:  C. Gibbs Free Energy (G)
EXPLANATION

Gibbs Free Energy (G = H - TS) is the appropriate thermodynamic potential for processes at constant T and P. ΔG = 0 at equilibrium and ΔG < 0 for spontaneous processes.

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