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Electronics (ECE)

Analog/digital electronics, communication

135 Q 4 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 41–50 of 135
Topics in Electronics (ECE)
Q.41 Easy Analog Circuits
A voltage-controlled voltage source (VCVS) has transconductance gm = 50 mS. If the input voltage is 10 mV, what is the output current?
A 0.5 mA
B 0.05 mA
C 5 mA
D 50 mA
Correct Answer:  A. 0.5 mA
EXPLANATION

Output current Id = gm × Vgs = 50 mS × 10 mV = 50 × 10⁻³ × 10 × 10⁻³ = 0.5 × 10⁻³ A = 0.5 mA

Test
Q.42 Easy Analog Circuits
In a two-stage cascaded amplifier, the first stage has gain A₁ = 50 and bandwidth BW₁ = 100 kHz, while the second stage has A₂ = 20 and BW₂ = 200 kHz. What is the overall voltage gain?
A 70
B 1000
C 250
D 150
Correct Answer:  B. 1000
EXPLANATION

In cascaded amplifiers, overall voltage gain = A₁ × A₂ = 50 × 20 = 1000. The bandwidth is determined by the stage with lowest bandwidth (100 kHz).

Test
Q.43 Easy Analog Circuits
A BJT is operated in the saturation region. Which of the following statements is true?
A Base-collector junction is reverse biased
B Both base-emitter and base-collector junctions are forward biased
C Collector-emitter voltage equals breakdown voltage
D Transistor acts as an open circuit
Correct Answer:  B. Both base-emitter and base-collector junctions are forward biased
EXPLANATION

In saturation, both junctions are forward biased: base-emitter junction is forward biased for current conduction, and base-collector junction is also forward biased, allowing maximum collector current.

Test
Q.44 Easy Analog Circuits
What is the primary advantage of a Darlington pair configuration in BJT amplifiers?
A Higher input impedance and current gain
B Lower output impedance
C Reduced power dissipation
D Higher frequency response
Correct Answer:  A. Higher input impedance and current gain
EXPLANATION

Darlington pairs consist of two transistors in cascade, providing extremely high current gain (β² product) and very high input impedance due to the two base-emitter junctions.

Test
Q.45 Easy Analog Circuits
A non-inverting amplifier is constructed with an op-amp having open-loop gain A₀ = 100,000. If Rf = 90 kΩ and Rin = 10 kΩ, what is the closed-loop voltage gain?
A 10
B 9
C 11
D 100
Correct Answer:  A. 10
EXPLANATION

For non-inverting amplifier: Acl = 1 + (Rf/Rin) = 1 + (90/10) = 1 + 9 = 10

Test
Q.46 Easy Analog Circuits
In a Common Emitter BJT amplifier, if the collector resistance is increased while keeping other parameters constant, how does the voltage gain change?
A Voltage gain increases
B Voltage gain decreases
C Voltage gain remains constant
D Voltage gain becomes zero
Correct Answer:  A. Voltage gain increases
EXPLANATION

Voltage gain Av = -gm × Rc, where gm is transconductance and Rc is collector resistance. Increasing Rc directly increases voltage gain.

Test
Q.47 Easy Analog Circuits
The input impedance of an op-amp in an ideal configuration is assumed to be:
A Infinite
B Zero
C Equal to the feedback resistance
D 1 MΩ
Correct Answer:  A. Infinite
EXPLANATION

Ideal op-amp assumptions include infinite input impedance (no current drawn at inputs), zero output impedance, and infinite open-loop gain.

Test
Q.48 Easy Analog Circuits
The gain-bandwidth product (GBW) of a typical general-purpose op-amp (like LM741) is approximately:
A 1 MHz
B 10 MHz
C 100 MHz
D 1 GHz
Correct Answer:  A. 1 MHz
EXPLANATION

LM741 has a GBW product of approximately 1 MHz, which is why it's limited to low-frequency applications. Modern op-amps have higher GBW.

Test
Q.49 Easy Analog Circuits
An op-amp integrator circuit has R = 10 kΩ and C = 100 nF. What is the time constant?
A 1 ms
B 10 ms
C 100 μs
D 1 μs
Correct Answer:  A. 1 ms
EXPLANATION

Time constant τ = RC = 10×10³ × 100×10⁻⁹ = 10×10⁻⁴ = 1×10⁻³ s = 1 ms.

Test
Q.50 Easy Analog Circuits
In a BJT amplifier biased in the active region, what is the relationship between collector current and base current?
A IC = β × IB
B IC = IB
C IC = VCE/RC
D IC is independent of IB
Correct Answer:  A. IC = β × IB
EXPLANATION

In the active region, IC = β × IB where β is the DC current gain (typically 50-300 for silicon BJTs).

Test
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