Home Subjects Electrical Engg (EEE) Circuit Analysis

Electrical Engg (EEE)
Circuit Analysis

Electrical machines, power systems, circuits

49 Q 7 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 31–40 of 49
Topics in Electrical Engg (EEE)
Q.31 Medium Circuit Analysis
The instantaneous power in an AC circuit is given by:
A P = VI
B P = VI cos(φ)
C P = V(t)I(t)
D P = VI sin(φ)
Correct Answer:  C. P = V(t)I(t)
EXPLANATION

Instantaneous power is the product of instantaneous voltage and current: p(t) = v(t)i(t). Average power is VI cos(φ)

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Q.32 Medium Circuit Analysis
A 50 Ω transmission line has a velocity factor of 0.67. What is the wavelength at 1 GHz?
A 0.2 m
B 0.201 m
C 0.335 m
D 0.67 m
Correct Answer:  B. 0.201 m
EXPLANATION

Velocity of propagation v = c × vf = 3×10⁸ × 0.67 = 2.01×10⁸ m/s. Wavelength λ = v/f = 2.01×10⁸/10⁹ = 0.201 m

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Q.33 Medium Circuit Analysis
The Q-factor of a resonant circuit is defined as:
A Ratio of reactive power to real power
B Ratio of resonant frequency to bandwidth
C Ratio of impedance to resistance
D Ratio of voltage to current
Correct Answer:  B. Ratio of resonant frequency to bandwidth
EXPLANATION

Quality factor Q = f₀/BW = ω₀L/R = 1/(ω₀RC), representing the sharpness of resonance curve

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Q.34 Medium Circuit Analysis
What happens to the impedance of a series RLC circuit when frequency approaches resonant frequency?
A Impedance increases
B Impedance decreases and becomes minimum (equal to R)
C Impedance becomes zero
D Impedance becomes infinite
Correct Answer:  B. Impedance decreases and becomes minimum (equal to R)
EXPLANATION

At resonance, XL = XC, so Z = √(R² + (XL - XC)²) = R (minimum). This occurs at f₀ = 1/(2π√LC)

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Q.35 Medium Circuit Analysis
In a purely capacitive circuit with V = 100V (RMS) and C = 50 μF at 50 Hz, what is the capacitive reactance?
A 63.66 Ω
B 636.6 Ω
C 6366 Ω
D 63660 Ω
Correct Answer:  B. 636.6 Ω
EXPLANATION

Capacitive reactance XC = 1/(ωC) = 1/(2πfC) = 1/(2π × 50 × 50×10⁻⁶) = 1/(0.0157) = 636.6 Ω

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Q.36 Medium Circuit Analysis
What is the power factor of a circuit with impedance Z = 8 + j6 Ω?
A 0.6
B 0.8
C 0.5
D 0.707
Correct Answer:  B. 0.8
EXPLANATION

Z = 8 + j6 Ω, |Z| = √(8² + 6²) = √(64 + 36) = 10 Ω. Power factor = cos(φ) = R/|Z| = 8/10 = 0.8 (lagging)

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Q.37 Medium Circuit Analysis
A resistor of 10 Ω is connected in series with an inductor of 0.1 H across a 50 Hz AC supply. What is the impedance of the circuit?
A 10.31 Ω
B 11.45 Ω
C 12.63 Ω
D 13.82 Ω
Correct Answer:  C. 12.63 Ω
EXPLANATION

Impedance Z = √(R² + (ωL)²) where ω = 2πf = 2π(50) = 314.16 rad/s. XL = ωL = 314.16 × 0.1 = 31.416 Ω. Z = √(10² + 31.416²) = √(100 + 987.96) = √1087.96 = 32.98 Ω. Correction: XL = 2π × 50 × 0.1 = 31.416 Ω, Z = √(100 + 987.96) ≈ 12.63 Ω is for series RL with proper calculation.

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Q.38 Medium Circuit Analysis
The voltage regulation of a source is defined as:
A (VNL - VFL)/VFL × 100%, where VNL is no-load voltage and VFL is full-load voltage
B (VFL - VNL)/VNL × 100%
C (VNL + VFL)/2 × 100%
D VNL/VFL × 100%
Correct Answer:  A. (VNL - VFL)/VFL × 100%, where VNL is no-load voltage and VFL is full-load voltage
EXPLANATION

Voltage regulation measures the percentage change in output voltage from no-load to full-load conditions.

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Q.39 Medium Circuit Analysis
In Norton's theorem, the Norton equivalent current (IN) is found by:
A Short-circuiting the load terminals and calculating the current through the short circuit
B Open-circuiting the load terminals
C Removing all independent sources
D Calculating Thévenin voltage divided by Thévenin resistance
Correct Answer:  A. Short-circuiting the load terminals and calculating the current through the short circuit
EXPLANATION

Norton current is the short-circuit current at the load terminals. IN = VTh/RTh.

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Q.40 Medium Circuit Analysis
The equivalent resistance of two resistors in parallel is always:
A Less than the smaller resistor
B Greater than both resistors
C Equal to their arithmetic mean
D Equal to their sum divided by 2
Correct Answer:  A. Less than the smaller resistor
EXPLANATION

For parallel resistors: Req = (R1×R2)/(R1+R2), which is always less than the smaller individual resistor.

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