A PID controller is used for a plant. If only the derivative gain Kd is increased while keeping Kp and Ki constant, what is the primary effect?

The correct answer is B: Increases system damping and reduces overshoot. The derivative term acts as damping in the system. Increasing Kd increases damping, which reduces overshoot and oscillations without affecting steady-state error significantly.

In a 4-bit ripple counter, the maximum frequency that can be counted is limited by the:

The correct answer is A: Propagation delay of each flip-flop stage. In ripple counters, each flip-flop must settle before the next one can toggle. The maximum countable frequency is limited by the total propagation delay through all stages.

In an AC bridge at balance condition, if R₁ = 100 Ω, R₂ = 50 Ω, and R₃ (inductive) = 200 Ω with series R, then R₄ is:

The correct answer is A: 100 Ω. Using AC bridge balance: Z₁/Z₂ = Z₃/Z₄; therefore 100/50 = 200/Z₄, which gives Z₄ = 100 Ω

A 3-phase induction motor draws 50 A at 0.8 power factor lagging from 400 V supply. The input power is approximately:

The correct answer is B: 27.71 kW. P = √3 × V × I × cosφ = 1.732 × 400 × 50 × 0.8 = 27,712 W ≈ 27.71 kW

In a bridge circuit at balance condition, the product of opposite resistances are equal. This principle is known as:

The correct answer is C: Wheatstone bridge condition. At Wheatstone bridge balance: R₁/R₂ = R₄/R₃ or R₁×R₃ = R₂×R₄. No current flows through galvanometer.

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Electrical Engg (EEE)
Circuit Analysis

Electrical machines, power systems, circuits

49 Q 7 Topics Take Mock Test

Difficulty: All Easy Medium Hard 41–49 of 49

Topics in Electrical Engg (EEE)

All Circuit Analysis 100 Electrical Machines 100 Power Systems 100 Control Systems 100 Power Electronics 100 Electrical Measurements 40 Digital Electronics 100

Q.41 Medium Circuit Analysis

In a series RLC circuit at resonance, the impedance is:

A Minimum and equal to R

B Maximum and equal to R

C Equal to XL + XC

D Equal to √(R² + L²)

Correct Answer: A. Minimum and equal to R

EXPLANATION

At resonance, XL = XC, so they cancel. Z = R (minimum), and current is maximum.

Test

Q.42 Medium Circuit Analysis

In a delta-wye (Δ-Y) conversion, if the delta resistances are RA, RB, RC, the wye resistance R1 (between node 1 and star point) is:

A (RA×RB)/(RA+RB+RC)

B RA+RB+RC

C (RA×RC)/(RA+RB+RC)

D RA/3

Correct Answer: A. (RA×RB)/(RA+RB+RC)

EXPLANATION

In Δ-Y conversion, each Y-resistor equals the product of adjacent Δ-resistors divided by the sum of all Δ-resistors.

Test

Q.43 Medium Circuit Analysis

The bandwidth of a resonant circuit is related to Q-factor by:

A BW = f₀/Q

B BW = Q/f₀

C BW = Q×f₀

D BW = f₀²/Q

Correct Answer: A. BW = f₀/Q

EXPLANATION

Bandwidth is inversely proportional to Q-factor. Higher Q means narrower bandwidth. BW = f₀/Q.

Test

Q.44 Medium Circuit Analysis

A bridge circuit is balanced when:

A Z1×Z3 = Z2×Z4

B Z1+Z2 = Z3+Z4

C Z1/Z2 = Z3/Z4

D Z1-Z2 = Z3-Z4

Correct Answer: A. Z1×Z3 = Z2×Z4

EXPLANATION

For a balanced AC bridge, the product of opposite arm impedances must be equal: Z1×Z3 = Z2×Z4.

Test

Q.45 Medium Circuit Analysis

A capacitor and inductor are in series with resonance occurring at 100 Hz. If L = 25 mH, the capacitance C is approximately:

A 101.3 µF

B 50.65 µF

C 202.6 µF

D 25.3 µF

Correct Answer: A. 101.3 µF

EXPLANATION

At resonance: f = 1/(2π√LC). C = 1/(4π²f²L) = 1/(4π²×10000×0.025) ≈ 101.3 µF.

Test

Q.46 Medium Circuit Analysis

In Thevenin's theorem, the Thevenin equivalent voltage (VTh) is found by:

A Open-circuiting the load and measuring voltage across its terminals

B Short-circuiting the load and measuring current

C Applying a test voltage at the terminals

D Calculating the average voltage across all elements

Correct Answer: A. Open-circuiting the load and measuring voltage across its terminals

EXPLANATION

Thevenin voltage is the open-circuit voltage measured across the load terminals after removing the load.

Test

Q.47 Medium Circuit Analysis

The Q-factor (quality factor) of a resonant circuit is defined as:

A Q = (1/R)√(L/C)

B Q = R√(L/C)

C Q = ω₀L/R or 1/(ω₀RC)

D Q = R/(ω₀L)

Correct Answer: C. Q = ω₀L/R or 1/(ω₀RC)

EXPLANATION

Q-factor represents selectivity and bandwidth characteristics. For series RLC: Q = ω₀L/R = 1/(ω₀RC) = (1/R)√(L/C).

Test

Q.48 Medium Circuit Analysis

In a parallel RC circuit, the total admittance Y is given by:

A Y = G + jωC where G = 1/R

B Y = G - jωC

C Y = √(G² + ω²C²)

D Y = G/(1 + ωC)

Correct Answer: A. Y = G + jωC where G = 1/R

EXPLANATION

In a parallel RC circuit, admittances add directly. Y = G + jBC where G = 1/R and BC = ωC.

Test

Q.49 Medium Circuit Analysis

A 10 Ω resistor and a 0.1 H inductor are connected in series to a 230V, 50Hz AC supply. The impedance of the circuit is approximately:

A 31.4 Ω

B 42.8 Ω

C 15.7 Ω

D 50 Ω

Correct Answer: A. 31.4 Ω

EXPLANATION

XL = 2πfL = 2π(50)(0.1) = 31.4 Ω. Z = √(10² + 31.4²) ≈ √(100 + 985.96) ≈ 33 Ω. Closest is 31.4 Ω.

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Electrical Engg (EEE) Circuit Analysis

Electrical Engg (EEE)
Circuit Analysis