Govt. Exams
Entrance Exams
Illuminance follows inverse square law: E ∝ 1/d²; when distance doubles, illuminance becomes 1/4th: 500/4 = 125 lux.
For two-wattmeter method in three-phase systems: tan(φ) = √3(W₁ - W₂)/(W₁ + W₂), used to calculate power factor.
Gauge factor = (ΔR/R₀)/strain; 2.1 = 5/(R₀ × 0.001); R₀ = 5/(2.1 × 0.001) ≈ 2381 Ω.
Kelvin's double bridge uses cross-connection to eliminate lead resistance errors when measuring very low resistances in industrial applications.
Using AC bridge balance: Z₁/Z₂ = Z₃/Z₄; therefore 100/50 = 200/Z₄, which gives Z₄ = 100 Ω
For unbalanced three-phase loads, three wattmeters are required—one in each phase—to measure total power accurately.
The voltmeter and resistor form a parallel circuit. Using voltage divider: V_true = 50 × (1000 + 100) / 1000 ≈ 54.55 V