Home Subjects Electrical Engg (EEE)

Electrical Engg (EEE)

Electrical machines, power systems, circuits

123 Q 7 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 81–90 of 123
Topics in Electrical Engg (EEE)
In a synchronous generator, the voltage regulation is negative when:
A Load power factor is leading
B Load power factor is lagging
C Load is purely resistive
D Load is purely inductive
Correct Answer:  A. Load power factor is leading
EXPLANATION

Leading power factor means reactive component opposes armature reaction, reducing terminal voltage drop

Test
In a synchronous generator connected to an infinite bus, if the excitation is increased beyond rated value:
A Real power output increases
B Frequency increases
C Generator draws leading reactive power from the bus
D Terminal voltage increases
Correct Answer:  C. Generator draws leading reactive power from the bus
EXPLANATION

In an infinite bus system, frequency and terminal voltage are fixed by the bus. Increasing excitation beyond rated value causes the generator to draw leading reactive power (operating as a synchronous condenser).

Test
A 3-phase, 50 Hz, 4-pole synchronous motor operates at rated speed. The excitation is reduced by 20%. What happens?
A Motor speed decreases
B Motor maintains speed but draws more reactive current (lagging)
C Motor maintains speed but draws more reactive current (leading)
D Motor loses synchronism and stalls
Correct Answer:  B. Motor maintains speed but draws more reactive current (lagging)
EXPLANATION

Synchronous motor speed depends only on frequency and poles. Reducing excitation causes the motor to draw more lagging reactive current to maintain synchronism, operating at lagging power factor.

Test
Which statement is correct regarding the torque-slip characteristic of a squirrel-cage induction motor?
A Torque is maximum at s = 0
B Torque is zero at s = 1
C Maximum torque occurs at slip s = Rr/Xr
D Torque increases linearly with slip throughout operating range
Correct Answer:  C. Maximum torque occurs at slip s = Rr/Xr
EXPLANATION

For induction motor, maximum torque occurs at slip s_max = R2/X2, where R2 and X2 are rotor resistance and reactance. This is derived from dT/ds = 0.

Test
The reluctance torque in a synchronous motor is maximum when the load angle is:
A
B 45°
C 90°
D 180°
Correct Answer:  B. 45°
EXPLANATION

Reluctance torque τrel ∝ sin(2δ), which is maximum when sin(2δ) = 1, i.e., when δ = 45°

Test
A 100 kW, 3-phase induction motor has a full-load slip of 0.04. The rotor copper loss at full load is:
A 3.2 kW
B 4 kW
C 4.8 kW
D 6.4 kW
Correct Answer:  B. 4 kW
EXPLANATION

Rotor copper loss = s × Pg, where Pg is air gap power. At full load, assuming 96% efficiency, losses ≈ 4.17 kW ≈ 4 kW

Test
The efficiency of a DC generator is maximum when:
A Iron loss equals copper loss
B Iron loss equals friction loss
C Copper loss equals friction and windage loss
D All losses are equal
Correct Answer:  C. Copper loss equals friction and windage loss
EXPLANATION

Maximum efficiency occurs when variable losses (copper) equal constant losses (friction, windage, and core losses).

Test
A transformer is operating at 110% of rated voltage. The core loss will be approximately:
A Same as rated
B 10% more than rated
C 21% more than rated
D 5% less than rated
Correct Answer:  C. 21% more than rated
EXPLANATION

Core loss Pc ∝ B² ∝ V². At 1.1V, loss = (1.1)² × rated loss = 1.21 × rated ≈ 21% increase

Test
In a synchronous motor, the pull-out torque depends on:
A Load torque only
B Excitation current only
C Supply voltage and field excitation
D Speed variation only
Correct Answer:  C. Supply voltage and field excitation
EXPLANATION

Pull-out torque τmax = 1.5(PΦIf)/(ωs), depends on pole flux and field current (excitation) and supply voltage.

Test
The equivalent circuit of an induction motor includes a series resistance R2/s in the rotor branch. The power dissipated in this resistance represents:
A Rotor copper loss
B Mechanical power output
C Core loss
D Stray loss
Correct Answer:  B. Mechanical power output
EXPLANATION

In equivalent circuit, voltage across R2/s is rotor voltage and current through it gives mechanical power = I2² × (R2/s - R2) = mechanical power developed.

Test
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