In root locus analysis, as the gain K increases from 0 to ∞, the closed-loop poles move along specific paths. Where do these paths originate?

The correct answer is B: At the poles of open-loop transfer function. The root locus starts at open-loop poles (K=0) and ends at open-loop zeros (K=∞). This is a fundamental property of root locus construction.

In a current-source inverter (CSI), the DC link component is typically:

The correct answer is B: An inductor with voltage source. CSI uses a large inductor in series with the DC source to maintain nearly constant current. This differs from VSI which uses a capacitor for constant voltage.

In a step-down DC-DC converter (buck converter), the output voltage is always:

The correct answer is B: Less than input voltage. A buck converter reduces voltage. Output voltage Vo = D × Vin, where D is duty cycle (0 < D < 1). For step-up, use boost converter.

In digital control systems, the sampling theorem requires sampling frequency to be:

The correct answer is A: Greater than twice the highest frequency in the signal. Nyquist sampling theorem: fs > 2·fmax to avoid aliasing. The sampling frequency must be at least twice the highest frequency component.

A shaded pole induction motor uses ________ for starting torque generation.

The correct answer is B: Shaded pole or copper ring. Shaded pole motors use a copper ring or shaded pole around part of the pole face to create a phase shift in the magnetic field, producing starting torque without additional components.

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Electrical Engg (EEE)

Electrical machines, power systems, circuits

321 Q 7 Topics Take Mock Test

Difficulty: All Easy Medium Hard 321–321 of 321

Topics in Electrical Engg (EEE)

All Circuit Analysis 100 Electrical Machines 100 Power Systems 100 Control Systems 100 Power Electronics 100 Electrical Measurements 40 Digital Electronics 100

Q.321 Medium Circuit Analysis

A 10 Ω resistor and a 0.1 H inductor are connected in series to a 230V, 50Hz AC supply. The impedance of the circuit is approximately:

A 31.4 Ω

B 42.8 Ω

C 15.7 Ω

D 50 Ω

Correct Answer: A. 31.4 Ω

EXPLANATION

XL = 2πfL = 2π(50)(0.1) = 31.4 Ω. Z = √(10² + 31.4²) ≈ √(100 + 985.96) ≈ 33 Ω. Closest is 31.4 Ω.

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