GPSC (Gujarat)

Cost price = 5000, Marked price = 5000 + 40% = 7000, Selling price = 7000 - 15% of 7000 = 5950. Profit = 950, Profit% = (950/5000)×100 = 19%

Since Bhuvan (170) > Charan > Deepak, both Charan and Deepak are shorter than 170 cm. Anil's height is unknown (could be equal or more).

Passed in Math only = 60-30 = 30, Passed in Science only = 50-30 = 20, Passed in both = 30. Total passed = 80. Failed in both = 100-80 = 20

# Letter-to-Number Coding Solution

This problem requires decoding the letter values from given word codes, then applying them to find the code for a new word.

Step 1: Decode Individual Letters from MOHAN

By comparing MOHAN = 57894, we assign each letter its corresponding digit position.

Step 2: Verify the Code with SOHAN

Cross-check using SOHAN = 35894 to confirm letter values remain consistent.

The values for O, H, A, N match perfectly, confirming our decoding is correct.

Step 3: Identify Missing Letter Values

From MOHINEE, we need the value for letter I and E, which weren't in the previous words.

Assuming sequential pattern or standard coding: \[\text{I} = 1, \text{ E} = 3\]

Step 4: Encode MOHINEE

Apply the decoded values to each letter in MOHINEE:

The answer is (B) 5789133

Selling price = 500 - (20% of 500) = 400. If profit = 25%, then CP = SP/1.25 = 400/1.25 = 320

Differences: 3, 5, 7, 9, 11. The differences increase by 2 each time. Next difference = 11, so 26+11 = 37

Using Venn diagram: Hindi only = 30-12 = 18, Gujarati only = 25-12 = 13, Both = 12. Total = 18+13+12 = 43. Neither = 50-43 = 7

Each letter is shifted by +1 position in the alphabet. R→S, A→B, J→K, etc. Applying the same to GUJARAT: G→H, U→V, J→K, A→B, R→S, A→B, T→U = HVKBSBU

Using Pythagoras theorem: Displacement = √(15² + 12²) = √(225 + 144) = √369 ≈ 19.2 ≈ 19 km.

Differences: 5, 7, 9, 11, 13. Pattern: n(n+2). For n=6: 6×8 = 48.