Govt. Exams
Entrance Exams
Newton's third law states that for every action, there is an equal and opposite reaction force.
f = μN = μmg = 0.25 × 8 × 10 = 20 N
At maximum height, v = 0. Using v = u - gt: 0 = 20 - 10t, so t = 2 s
Using s = ut + ½at², where u = 0, s = 100 m, t = 5 s: 100 = 0 + ½a(25), a = 8 m/s²
Maximum resultant occurs when forces act in the same direction: R = 12 + 5 = 17 N
Using F = ma, where a = (v-u)/t = (0-10)/2 = -5 m/s². Therefore F = 5 × 5 = 25 N
At maximum height, v = 0. Using v = u - gt, 0 = 20 - 10t, therefore t = 2 s
Net force = 5000 - 2000 = 3000 N. Using F = ma, a = 3000/1000 = 3 m/s²
At rest, normal force equals weight. N = mg, 10 = m × 10, therefore m = 1 kg
Net force = √(3² + 4²) = 5 N. Using F = ma, a = 5/2 = 2.5 m/s²