Home Subjects NEET Physics Mechanics & Laws of Motion

NEET Physics
Mechanics & Laws of Motion

Physics questions for NEET UG — Mechanics, Thermodynamics, Optics, Modern Physics.

37 Q 2 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 1–10 of 37
Topics in NEET Physics
All Mechanics & Laws of Motion 100 Thermodynamics 100
Which statement best describes Newton's third law of motion?
A Force equals mass times acceleration
B Action and reaction forces are equal in magnitude and opposite in direction
C Objects in motion remain in motion unless acted upon by external force
D The net force on an object determines its acceleration
Correct Answer:  B. Action and reaction forces are equal in magnitude and opposite in direction
EXPLANATION

Newton's third law states that for every action, there is an equal and opposite reaction force.

Test
An object of mass 8 kg is on a horizontal surface with coefficient of kinetic friction 0.25. What is the friction force when the object is moving? (g = 10 m/s²)
A 10 N
B 20 N
C 40 N
D 80 N
Correct Answer:  B. 20 N
EXPLANATION

f = μN = μmg = 0.25 × 8 × 10 = 20 N

Test
A ball is thrown vertically upward with an initial velocity of 20 m/s. How long does it take to reach maximum height? (g = 10 m/s²)
A 1 s
B 2 s
C 3 s
D 4 s
Correct Answer:  B. 2 s
EXPLANATION

At maximum height, v = 0. Using v = u - gt: 0 = 20 - 10t, so t = 2 s

Test
A car accelerates uniformly from rest and covers 100 m in 5 seconds. What is its acceleration?
A 8 m/s²
B 10 m/s²
C 16 m/s²
D 20 m/s²
Correct Answer:  A. 8 m/s²
EXPLANATION

Using s = ut + ½at², where u = 0, s = 100 m, t = 5 s: 100 = 0 + ½a(25), a = 8 m/s²

Test
Two forces of 12 N and 5 N act on a body. The maximum resultant force possible is:
A 7 N
B 17 N
C 12 N
D 5 N
Correct Answer:  B. 17 N
EXPLANATION

Maximum resultant occurs when forces act in the same direction: R = 12 + 5 = 17 N

Test
A body of mass 5 kg is moving with a velocity of 10 m/s. What force is required to stop it in 2 seconds?
A 25 N
B 50 N
C 75 N
D 100 N
Correct Answer:  A. 25 N
EXPLANATION

Using F = ma, where a = (v-u)/t = (0-10)/2 = -5 m/s². Therefore F = 5 × 5 = 25 N

Test
An object is thrown vertically upward with initial velocity 20 m/s. At what time does it reach maximum height? (g = 10 m/s²)
A 1 s
B 2 s
C 3 s
D 4 s
Correct Answer:  B. 2 s
EXPLANATION

At maximum height, v = 0. Using v = u - gt, 0 = 20 - 10t, therefore t = 2 s

Test
A car of mass 1000 kg experiences friction of 2000 N while moving. If the engine provides 5000 N of force, what is the net acceleration?
A 2 m/s²
B 3 m/s²
C 4 m/s²
D 5 m/s²
Correct Answer:  B. 3 m/s²
EXPLANATION

Net force = 5000 - 2000 = 3000 N. Using F = ma, a = 3000/1000 = 3 m/s²

Test
A book rests on a table. The normal force on the book is 10 N. What is the weight of the book? (g = 10 m/s²)
A 0.5 kg
B 1 kg
C 2 kg
D Cannot be determined
Correct Answer:  B. 1 kg
EXPLANATION

At rest, normal force equals weight. N = mg, 10 = m × 10, therefore m = 1 kg

Test
A 2 kg mass is subjected to forces of 3 N (east) and 4 N (north). What is the magnitude of acceleration?
A 1.5 m/s²
B 2.0 m/s²
C 2.5 m/s²
D 3.5 m/s²
Correct Answer:  C. 2.5 m/s²
EXPLANATION

Net force = √(3² + 4²) = 5 N. Using F = ma, a = 5/2 = 2.5 m/s²

Test
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