Home Subjects NEET Physics Mechanics & Laws of Motion

NEET Physics
Mechanics & Laws of Motion

Physics questions for NEET UG — Mechanics, Thermodynamics, Optics, Modern Physics.

37 Q 2 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 31–37 of 37
Topics in NEET Physics
All Mechanics & Laws of Motion 100 Thermodynamics 100
A stone is thrown vertically upward from the ground. At the highest point, the velocity is zero but acceleration is not. What is the acceleration at the highest point?
A Zero
B g (downward)
C g (upward)
D 2g (downward)
Correct Answer:  B. g (downward)
EXPLANATION

At the highest point, velocity is zero, but the gravitational force continues to act, producing an acceleration of g = 10 m/s² downward.

Test
A book rests on a table. The normal force exerted by the table on the book is an example of:
A Action-reaction pair
B Applied force
C Contact force
D Field force
Correct Answer:  C. Contact force
EXPLANATION

Normal force is a contact force arising from physical contact between the table and book. The action-reaction pair would be the weight of the book and the force the book exerts on the table.

Test
Three forces of 10 N, 20 N, and 30 N act on a body in the same direction. What is the resultant force?
A 10 N
B 20 N
C 30 N
D 60 N
Correct Answer:  D. 60 N
EXPLANATION

When forces act in the same direction, the resultant is the sum of all forces: 10 + 20 + 30 = 60 N.

Test
Which of the following is NOT a consequence of Newton's third law of motion?
A Action and reaction forces are equal in magnitude
B Action and reaction act on the same body
C Action and reaction are opposite in direction
D Action and reaction act for the same time period
Correct Answer:  B. Action and reaction act on the same body
EXPLANATION

Newton's third law states action and reaction act on different bodies, not the same body. They are equal in magnitude, opposite in direction, and act simultaneously.

Test
A 5 kg object experiences a net force of 20 N. What is its acceleration?
A 2 m/s²
B 4 m/s²
C 100 m/s²
D 0.25 m/s²
Correct Answer:  B. 4 m/s²
EXPLANATION

Using F = ma, we get a = F/m = 20/5 = 4 m/s².

Test
If the mass of an object is doubled and the force applied remains the same, how does the acceleration change?
A Doubles
B Becomes half
C Remains same
D Becomes four times
Correct Answer:  B. Becomes half
EXPLANATION

From Newton's second law, F = ma. If F is constant and m doubles, then a = F/2m, so acceleration becomes half.

Test
A body is moving with a constant velocity of 10 m/s. What is the net force acting on it?
A 0 N
B 10 N
C 100 N
D Cannot be determined
Correct Answer:  A. 0 N
EXPLANATION

According to Newton's first law, when velocity is constant, acceleration is zero. Therefore, net force F = ma = m × 0 = 0 N.

Test
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