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247 Q 5 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 191–200 of 247
Topics in Chemical Engineering
Q.191 Medium Heat Transfer
In steady-state heat conduction through a composite wall with three layers in series, if the thermal conductivities are k₁ > k₂ > k₃, which layer will have the maximum temperature drop?
A Layer 1
B Layer 2
C Layer 3
D Temperature drop is equal in all layers
Correct Answer:  C. Layer 3
EXPLANATION

Temperature drop across a layer is inversely proportional to thermal conductivity (ΔT ∝ 1/k). Since k₃ is smallest, layer 3 experiences maximum temperature drop.

Test
Q.192 Medium Heat Transfer
In unsteady-state conduction with Bi
A Lumped capacitance method - uniform internal temperature
B Temperature varies spatially and temporally
C Steady-state conditions apply
D Conduction resistance is infinite
Correct Answer:  A. Lumped capacitance method - uniform internal temperature
EXPLANATION

When Bi < 0.1, convective resistance is much larger than conductive resistance, allowing assumption of uniform temperature throughout the object.

Test
Q.193 Medium Heat Transfer
For natural convection from a vertical isothermal plate in air, which correlation applies best?
A Nu = C × (Gr × Pr)^n, where n ≈ 0.25 for laminar
B Nu = 0.023 × Re^0.8 × Pr^0.4
C Nu = constant
D Nu = 3.66 + (other terms)
Correct Answer:  A. Nu = C × (Gr × Pr)^n, where n ≈ 0.25 for laminar
EXPLANATION

For natural convection: Nu = C(Ra)^n where Ra = Gr×Pr. For laminar boundary layer (Ra < 10^9), n ≈ 0.25. For turbulent (Ra > 10^9), n ≈ 0.33.

Test
Q.194 Medium Heat Transfer
For a flat plate solar collector with selective coating, which of the following is most desirable?
A High absorptivity (α) and high emissivity (ε) in solar spectrum
B High absorptivity (α) in solar spectrum and low emissivity (ε) in IR range
C Low absorptivity (α) and low emissivity (ε)
D Equal α and ε values
Correct Answer:  B. High absorptivity (α) in solar spectrum and low emissivity (ε) in IR range
EXPLANATION

Selective coatings should absorb solar radiation (high α_sol) but minimize thermal radiation losses (low ε_IR), maximizing collector efficiency.

Test
Q.195 Medium Heat Transfer
In a shell-and-tube heat exchanger (1 shell pass, 2 tube passes), the effectiveness is lower than counter-current primarily because:
A Part of the flow behaves co-currently
B Fouling resistance is higher
C Pressure drop increases
D Material properties change
Correct Answer:  A. Part of the flow behaves co-currently
EXPLANATION

In 1-2 arrangement, portion of shell-side flows co-currently with tube-side, reducing overall effectiveness compared to true counter-current.

Test
Q.196 Medium Heat Transfer
For turbulent flow in smooth pipes (Pr > 0.6), which correlation is most commonly used?
A Dittus-Boelert: Nu = 0.023 Re^0.8 Pr^0.4
B Sieder-Tate: Nu = 0.027 Re^0.8 Pr^(1/3)
C Gnielinski equation
D Laminar correlation only
Correct Answer:  A. Dittus-Boelert: Nu = 0.023 Re^0.8 Pr^0.4
EXPLANATION

Dittus-Boelert correlation is the most widely used for turbulent flow with Pr > 0.6. Valid for Re > 10,000, smooth pipes, and fully developed flow.

Test
Q.197 Medium Heat Transfer
The log mean temperature difference (LMTD) correction factor F is required primarily for which configuration?
A Counter-current heat exchangers
B Cross-flow and more complex arrangements
C Co-current heat exchangers
D Double-pipe heat exchangers only
Correct Answer:  B. Cross-flow and more complex arrangements
EXPLANATION

F-correction factor is used for non-counter-current arrangements (cross-flow, 1-2 shell-tube, etc.) where LMTD doesn't directly apply without correction.

Test
Q.198 Medium Heat Transfer
The Number of Transfer Units (NTU) is defined as which of the following?
A UA/(ṁC_p)_min
B ΔT_LMTD/ΔT_m
C Q_actual/Q_max
D hA/C_p
Correct Answer:  A. UA/(ṁC_p)_min
EXPLANATION

NTU = UA/(ṁC_p)_min is the ratio of overall heat transfer capacity to minimum heat capacity rate, used in ε-NTU method.

Test
Q.199 Medium Heat Transfer
In a counter-current heat exchanger with equal heat capacities, what is the maximum possible effectiveness?
A 100% or 1.0
B 50%
C Limited by NTU
D Cannot be determined
Correct Answer:  A. 100% or 1.0
EXPLANATION

For counter-current arrangement, maximum effectiveness can approach 1.0 (100%) with infinite NTU. For co-current, it's limited to (1-exp(-NTU(1+C_r)))/(1+C_r).

Test
Q.200 Medium Heat Transfer
For fully developed laminar flow in a circular pipe with constant wall heat flux, which Nusselt number (Nu) is approximately correct?
A Nu ≈ 3.66
B Nu ≈ 4.36
C Nu ≈ 5.33
D Nu ≈ 8.24
Correct Answer:  B. Nu ≈ 4.36
EXPLANATION

For constant heat flux boundary condition (H1 type) in circular pipes with fully developed laminar flow, Nu ≈ 4.36. For constant wall temperature (H2), Nu ≈ 3.66.

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