Home Subjects Electronics (ECE) Digital Electronics

Electronics (ECE)
Digital Electronics

Analog/digital electronics, communication

39 Q 4 Topics Take Mock Test
Advertisement
Difficulty: All Easy Medium Hard 31–39 of 39
Topics in Electronics (ECE)
A JK flip-flop with J=1, K=1 performs:
A No change
B Set operation
C Reset operation
D Toggle operation
Correct Answer:  D. Toggle operation
EXPLANATION

JK flip-flop truth table: J=0,K=0 (No change), J=1,K=0 (Set), J=0,K=1 (Reset), J=1,K=1 (Toggle). When both are 1, output toggles.

Test
A full adder has how many inputs and outputs?
A 2 inputs, 1 output
B 3 inputs, 2 outputs
C 4 inputs, 2 outputs
D 3 inputs, 3 outputs
Correct Answer:  B. 3 inputs, 2 outputs
EXPLANATION

Full adder has 3 inputs (A, B, Cin) and 2 outputs (Sum, Cout). It differs from half adder which has 2 inputs and 2 outputs.

Test
The BCD equivalent of decimal 47 is:
A 0100 0111
B 0101 0110
C 0100 0101
D 0110 0111
Correct Answer:  A. 0100 0111
EXPLANATION

In BCD, each decimal digit is converted separately to 4-bit binary. 4 = 0100, 7 = 0111. So 47 in BCD = 0100 0111.

Test
A multiplexer with 8 inputs requires how many select lines?
A 2
B 3
C 4
D 8
Correct Answer:  B. 3
EXPLANATION

For n select lines, 2^n inputs are possible. For 8 inputs: 2^n = 8, so n = 3. An 8:1 multiplexer needs 3 select lines (A, B, C).

Test
In Gray code, consecutive numbers differ by:
A One bit only
B Two bits
C Three bits
D Variable number of bits
Correct Answer:  A. One bit only
EXPLANATION

Gray code (Reflected Binary Code) is designed such that successive values differ by only one bit. This is useful in error detection and mechanical encoders.

Test
The decimal equivalent of binary number 10110.101 is:
A 22.625
B 23.625
C 24.625
D 25.625
Correct Answer:  A. 22.625
EXPLANATION

10110.101 = 1×16 + 0×8 + 1×4 + 1×2 + 0×1 + 1×0.5 + 0×0.25 + 1×0.125 = 16 + 4 + 2 + 0.5 + 0.125 = 22.625

Test
How many 2-input NAND gates are required to implement a 2-input AND gate?
A 1
B 2
C 3
D 4
Correct Answer:  B. 2
EXPLANATION

AND gate can be implemented using two NAND gates. First NAND gate as AND, second NAND gate as NOT (both inputs same) to negate the output.

Test
The output of a NAND gate is 0 when:
A At least one input is 0
B All inputs are 1
C At least one input is 1
D All inputs are 0
Correct Answer:  B. All inputs are 1
EXPLANATION

NAND gate output is 0 only when all inputs are 1. NAND is NOT of AND operation. For 2-input: output is 0 only when both inputs are 1.

Test
Which of the following is NOT a basic logic gate?
A AND gate
B OR gate
C XOR gate
D NOT gate
Correct Answer:  C. XOR gate
EXPLANATION

XOR is a derived logic gate made from combination of basic gates (AND, OR, NOT). The three basic gates are AND, OR, and NOT.

Test
IGET
IGET AI
Online · Exam prep assistant
Hi! 👋 I'm your iget AI assistant.

Ask me anything about exam prep, MCQ solutions, study tips, or strategies! 🎯
UPSC strategy SSC CGL syllabus Improve aptitude NEET Biology tips