Home Subjects Electronics (ECE) Digital Electronics

Electronics (ECE)
Digital Electronics

Analog/digital electronics, communication

50 Q 4 Topics Take Mock Test
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Topics in Electronics (ECE)
Which encoding scheme minimizes errors during binary-to-decimal conversion in digital systems?
A Pure Binary
B Gray Code
C BCD
D Excess-3
Correct Answer:  B. Gray Code
EXPLANATION

Gray Code changes only one bit between consecutive numbers, minimizing transition errors. This prevents multiple simultaneous bit transitions that could cause undefined intermediate states

Test
In a cascaded 4-bit counter system where two 4-bit counters are connected, what maximum count value can be achieved?
A 2⁴ - 1 = 15
B 2⁸ - 1 = 255
C 2⁴ + 2⁴ = 32
D 4⁴ = 256
Correct Answer:  B. 2⁸ - 1 = 255
EXPLANATION

Two cascaded 4-bit counters form an 8-bit counter system. Maximum count = 2⁸ - 1 = 255 (counts from 0 to 255, total 256 states)

Test
What is the hold time in a flip-flop, and why is it critical?
A Time to hold data in memory; prevents data loss
B Minimum time input must remain stable after clock edge; prevents metastability
C Time required to reset the flip-flop
D Duration output remains HIGH
Correct Answer:  B. Minimum time input must remain stable after clock edge; prevents metastability
EXPLANATION

Hold time (th) is the minimum duration input must remain stable after the clock edge. Violation can cause metastability—a state where flip-flop output is uncertain or oscillates unpredictably

Test
In a magnitude comparator for 4-bit numbers, if A > B, A = B, and A < B outputs are provided, what is the total number of output combinations possible?
A 16 combinations
B 3 combinations
C 256 combinations
D 48 combinations
Correct Answer:  B. 3 combinations
EXPLANATION

A magnitude comparator produces exactly 3 mutually exclusive outputs: A>B (1,0,0) or A=B (0,1,0) or A<B (0,0,1). These are the only 3 possible comparison results for any input pair

Test
A 4-bit binary subtractor using 2's complement method requires:
A 4 full adders and complementing circuit
B 4 full subtractors only
C 3 full adders and 1 full subtractor
D Separate subtraction logic circuits
Correct Answer:  A. 4 full adders and complementing circuit
EXPLANATION

2's complement subtraction (A-B) converts to addition A+2's complement of B. This requires 4 full adders (for addition) and XOR gates (for bit complementing), avoiding dedicated subtractors

Test
Which multiplexer configuration is used to implement any Boolean function with minimum gates?
A 2-to-1 multiplexer
B 4-to-1 multiplexer
C n-to-1 multiplexer with 2ⁿ inputs
D 8-to-1 multiplexer
Correct Answer:  C. n-to-1 multiplexer with 2ⁿ inputs
EXPLANATION

An n-variable Boolean function can be efficiently implemented using a 2ⁿ-to-1 multiplexer where variables form select lines and minterms form data inputs, achieving minimal gate implementation

Test
For a modulo-6 counter using JK flip-flops, how many flip-flops are required at minimum?
A 2 flip-flops
B 3 flip-flops
C 4 flip-flops
D 6 flip-flops
Correct Answer:  B. 3 flip-flops
EXPLANATION

For modulo-N counter, minimum flip-flops required = ⌈log₂(N)⌉. For modulo-6: ⌈log₂(6)⌉ = ⌈2.58⌉ = 3 flip-flops (counts 0-5)

Test
What is the setup time in a flip-flop?
A Time required for output to stabilize after clock pulse
B Minimum time input must be stable before clock edge
C Time taken to reset the flip-flop
D Delay between input and output
Correct Answer:  B. Minimum time input must be stable before clock edge
EXPLANATION

Setup time (tsu) is the minimum duration the input signal must remain stable and valid before the active clock edge for reliable capture and state change

Test
In Booth's multiplication algorithm, which sequence of multiplier bits requires the fewest operations?
A Alternating 1s and 0s
B Consecutive 1s
C All 1s
D Consecutive 0s
Correct Answer:  B. Consecutive 1s
EXPLANATION

Booth's algorithm replaces consecutive 1s with a single subtraction and addition operation. Consecutive 1s (like 0111) are treated as 1000-1, reducing computation steps compared to processing each 1 individually

Test
In a synchronous counter design, what is the main advantage over asynchronous counters?
A Lower power consumption
B Simpler circuit design
C Higher operating frequency without timing issues
D Fewer flip-flops required
Correct Answer:  C. Higher operating frequency without timing issues
EXPLANATION

Synchronous counters clock all flip-flops simultaneously, eliminating propagation delay problems. This allows higher operating frequencies without cumulative timing errors present in ripple counters

Test
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