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Electronics (ECE)

Analog/digital electronics, communication

78 Q 4 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 31–40 of 78
Topics in Electronics (ECE)
Q.31 Hard Analog Circuits
A feedback amplifier with closed-loop gain Acl = 10 has feedback fraction β = 0.1. What is the open-loop gain (A)?
A 100
B 1000
C 50
D 200
Correct Answer:  B. 1000
EXPLANATION

From Acl = A/(1 + Aβ), we get 10 = A/(1 + A×0.1). Solving: 10(1 + 0.1A) = A → 10 = 0.9A → A ≈ 1000 (for high gain).

Test
Q.32 Hard Analog Circuits
In a differential amplifier, Common Mode Rejection Ratio (CMRR) is measured as 80 dB. What is the numerical ratio of differential gain to common mode gain?
A 100
B 1000
C 10000
D 100000
Correct Answer:  C. 10000
EXPLANATION

CMRR (dB) = 20 log₁₀(Ad/Ac); 80 = 20 log₁₀(ratio), therefore ratio = 10^(80/20) = 10^4 = 10000.

Test
Q.33 Hard Analog Circuits
In a Common Emitter amplifier, if the input impedance is 1 kΩ and the output impedance is 50 kΩ, what is the approximate voltage gain if β = 100 and gm = 0.04 S?
A 1000
B 2000
C 500
D 200
Correct Answer:  B. 2000
EXPLANATION

Voltage gain = gm × Rc (where Rc ≈ output impedance) = 0.04 × 50k = 2000 for a CE amplifier configuration.

Test
Q.34 Hard Analog Circuits
Which statement about thermal stability in BJT amplifiers is CORRECT?
A Thermal runaway occurs due to negative temperature coefficient of VBE
B As temperature increases, ICO decreases exponentially
C Stabilization requires RE without bypass capacitor for DC path
D Thermal stability is independent of supply voltage
Correct Answer:  C. Stabilization requires RE without bypass capacitor for DC path
EXPLANATION

Thermal stability improved by: (1) RE without bypass for DC stabilization, (2) lower supply voltage, (3) smaller β transistor, (4) heat sinking. VBE decreases with temperature (negative TC), increasing base current and ICO, causing thermal runaway.

Test
Q.35 Hard Analog Circuits
The Barkhausen criterion for oscillation states that
A Loop gain should be >1
B Loop gain = 1 AND phase shift = 0° (or 360°)
C Loop gain = 1 with 90° phase shift
D Only phase shift = 180° is required
Correct Answer:  B. Loop gain = 1 AND phase shift = 0° (or 360°)
EXPLANATION

Barkhausen criterion: For sustained oscillations, |Aβ| = 1 (unity gain) AND total phase shift = 0° (or 360°). Both conditions must be satisfied simultaneously.

Test
Q.36 Hard Analog Circuits
Negative feedback in an amplifier primarily results in
A Increased gain
B Decreased gain but improved stability and reduced distortion
C No change in gain
D Increased bandwidth at the cost of gain
Correct Answer:  B. Decreased gain but improved stability and reduced distortion
EXPLANATION

Negative feedback reduces gain by factor (1+Aβ) but provides benefits: improved linearity, reduced distortion, increased input impedance (series feedback), decreased output impedance (shunt feedback).

Test
Q.37 Hard Analog Circuits
The Miller effect in a common emitter amplifier causes
A Increase in input capacitance
B Decrease in voltage gain
C Reduction in bandwidth
D All of the above
Correct Answer:  D. All of the above
EXPLANATION

Miller effect refers to the multiplication of base-collector capacitance by (1+Av) at the input, increasing input capacitance, reducing input impedance, and decreasing bandwidth.

Test
A combinational logic circuit implements a function where output Y = (A'BC) + (AB'C) + (ABC'). After minimization using K-map, the circuit requires minimum number of gates. Which of the following is the simplified expression?
A Y = AB + BC + AC
B Y = C(A'B + AB') + ABC'
C Y = C(A ⊕ B) + ABC'
D Y = AC + AB
Correct Answer:  C. Y = C(A ⊕ B) + ABC'
EXPLANATION

Using K-map for three variables: (A'BC) + (AB'C) + (ABC') = C(A'B + AB') + ABC' = C(A ⊕ B) + ABC'. This represents XOR operation with an additional term, which is the minimal form requiring fewer gates than other options.

Test
In a pipelined architecture with 5 stages, what is the ideal speedup compared to non-pipelined execution?
A 2x
B 3x
C 5x
D 10x
Correct Answer:  C. 5x
EXPLANATION

Ideal speedup in pipelining equals the number of pipeline stages. With 5 stages and optimal conditions, speedup is approximately 5x.

Test
What is the maximum frequency operation for a circuit with total propagation delay of 50 ns?
A 20 MHz
B 50 MHz
C 2 MHz
D 200 MHz
Correct Answer:  A. 20 MHz
EXPLANATION

Maximum frequency = 1 / (propagation delay) = 1 / 50 ns = 1 / (50 × 10^-9 s) = 20 MHz.

Test
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