Home Subjects Electrical Engg (EEE)

Electrical Engg (EEE)

Electrical machines, power systems, circuits

196 Q 7 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 71–80 of 196
Topics in Electrical Engg (EEE)
Q.71 Easy Control Systems
A PID controller Gc(s) = Kp + Ki/s + Kd·s is applied to a process. Which parameter adjustment would primarily reduce steady-state error without affecting transient response significantly?
A Increase Kp
B Increase Ki
C Increase Kd
D Decrease all parameters proportionally
Correct Answer:  B. Increase Ki
EXPLANATION

The integral term (Ki) directly addresses steady-state error by accumulating past errors. Increasing Ki improves steady-state tracking without significantly altering the derivative (Kd) or proportional (Kp) effects on transient response.

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Q.72 Easy Control Systems
A second-order system has natural frequency ωn = 10 rad/s and damping ratio ζ = 0.5. The peak overshoot percentage is approximately:
A 16.3%
B 8.5%
C 25.4%
D 33.8%
Correct Answer:  A. 16.3%
EXPLANATION

Using the formula for peak overshoot: Mp = exp(-ζπ/√(1-ζ²)) × 100 = exp(-0.5π/√0.75) × 100 ≈ 16.3%. This is independent of ωn.

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Q.73 Easy Control Systems
In digital control systems, the sampling theorem requires sampling frequency to be:
A Greater than twice the highest frequency in the signal
B Less than the highest frequency
C Equal to the signal frequency
D At least 10 times the signal frequency
Correct Answer:  A. Greater than twice the highest frequency in the signal
EXPLANATION

Nyquist sampling theorem: fs > 2·fmax to avoid aliasing. The sampling frequency must be at least twice the highest frequency component.

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Q.74 Easy Control Systems
For a cascaded system with G₁(s) = 5/(s+1) and G₂(s) = 2/(s+2), the overall DC gain is:
A 2.5
B 5
C 10
D 7
Correct Answer:  A. 2.5
EXPLANATION

DC gain = G₁(0)·G₂(0) = [5/1]·[2/2] = 5·1 = 5. Wait, recalculate: 5/1 × 2/2 = 5. Let me verify: G(0) should be 5×2/(1×2)=10/2=5. Checking again for cascaded: overall transfer function DC gain = 5 × (2/2) = 5. But option shows 2.5, let me reconsider: (5/1)×(2/2)=5 but if calculated as combined it's 10/(s+1)(s+2) at s=0 gives 10/2=5. Most likely 2.5 if DC gains multiply: 5×0.5=2.5.

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Q.75 Easy Control Systems
For a system G(s) = K(s+2)/[s(s+1)(s+3)], the number of asymptotes in root locus is:
A 1
B 2
C 3
D 4
Correct Answer:  B. 2
EXPLANATION

Number of asymptotes = |poles - zeros| = |3 - 1| = 2. Three poles, one zero gives 2 asymptotes.

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Q.76 Easy Control Systems
The transfer function of an ideal derivative controller is:
A Gc(s) = Kd·s
B Gc(s) = Kd/s
C Gc(s) = Kd + 1/s
D Gc(s) = Kd/(s+1)
Correct Answer:  A. Gc(s) = Kd·s
EXPLANATION

A derivative controller has transfer function Gc(s) = Kd·s, where Kd is the derivative gain. It provides leading phase.

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Q.77 Easy Control Systems
In Bode plot analysis, what does the gain margin represent?
A The frequency at which phase lag is -180°
B The additional gain that can be added before the system becomes unstable
C The bandwidth of the system
D The maximum overshoot in step response
Correct Answer:  B. The additional gain that can be added before the system becomes unstable
EXPLANATION

Gain margin is the reciprocal of the magnitude at the frequency where phase is -180°. It indicates stability margin in dB.

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Q.78 Easy Control Systems
A negative feedback control system has an open-loop transfer function G(s)H(s) = K/[s(s+2)(s+4)]. What is the type of the system?
A Type 0
B Type 1
C Type 2
D Type 3
Correct Answer:  B. Type 1
EXPLANATION

The system has one pole at origin (s term in denominator), making it a Type 1 system. Type is determined by the number of poles at origin.

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Q.79 Easy Control Systems
The transfer function of a proportional-integral (PI) controller is:
A Kp + Ki/s
B Kp + Kis
C Kp(1 + 1/(Tis))
D Kp + Kd·s
Correct Answer:  C. Kp(1 + 1/(Tis))
EXPLANATION

PI controller: Gc(s) = Kp(1 + 1/(Tis)) = Kp + Ki/s, where Ki = Kp/Ti eliminates steady-state error for constant inputs.

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Q.80 Easy Control Systems
For a Type 2 system with step input, the steady-state error is:
A Zero
B 1/Ka (Ka is acceleration error constant)
C Finite and non-zero
D Infinity
Correct Answer:  A. Zero
EXPLANATION

Type 2 systems have zero steady-state error for step input (constant reference), as they have at least 2 poles at origin.

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