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Electrical Engg (EEE)

Electrical machines, power systems, circuits

196 Q 7 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 81–90 of 196
Topics in Electrical Engg (EEE)
Q.81 Easy Control Systems
Which of the following is a characteristic of a lag compensator?
A Increases system bandwidth
B Improves steady-state accuracy
C Increases system speed
D Reduces overshoot significantly
Correct Answer:  B. Improves steady-state accuracy
EXPLANATION

Lag compensator reduces steady-state error by increasing the DC gain without significantly affecting transient response or stability margins.

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Q.82 Easy Control Systems
A second-order system has damping ratio ζ = 0.5. This system is classified as:
A Critically damped
B Underdamped
C Overdamped
D Unstable
Correct Answer:  B. Underdamped
EXPLANATION

For ζ < 1, the system is underdamped with oscillatory response. ζ = 0.5 falls in this category.

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Q.83 Easy Control Systems
In a Bode plot, the magnitude plot slope in dB/decade for a pole at origin is:
A -20 dB/decade
B -40 dB/decade
C +20 dB/decade
D +40 dB/decade
Correct Answer:  A. -20 dB/decade
EXPLANATION

Each pole contributes -20 dB/decade slope. A single pole at origin contributes -20 dB/decade.

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Q.84 Easy Control Systems
A control system has an open-loop transfer function G(s)H(s) = K/[s(s+2)(s+4)]. What is the type of this system?
A Type 0
B Type 1
C Type 2
D Type 3
Correct Answer:  B. Type 1
EXPLANATION

The type of a system is determined by the number of poles at origin. Here, there is one pole at origin (s term), making it Type 1.

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Q.85 Easy Control Systems
A system with characteristic equation s³ + 6s² + 11s + 6 = 0 has poles at:
A -1, -2, -3
B -1, -2, -4
C -1, -3, -4
D -2, -2, -3
Correct Answer:  A. -1, -2, -3
EXPLANATION

Factoring: (s+1)(s+2)(s+3) = 0 gives poles at s = -1, -2, -3. All in LHP, so system is stable

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Q.86 Easy Control Systems
The corner frequency of a transfer function H(s) = 1/(1 + s/10) occurs at:
A 1 rad/s
B 10 rad/s
C 0.1 rad/s
D 100 rad/s
Correct Answer:  B. 10 rad/s
EXPLANATION

Corner frequency = pole frequency. Rewriting: H(s) = 10/(s+10), so pole at -10, corner frequency = 10 rad/s

Test
Q.87 Easy Control Systems
The static error constant for a Type-1 system with G(s) = 20/(s(s+5)(s+10)) is:
A 0.4
B 0.2
C 2.0
D 4.0
Correct Answer:  A. 0.4
EXPLANATION

For Type-1 system, Kv = lim s→0 s·G(s) = 20/(5·10) = 20/50 = 0.4

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Q.88 Easy Control Systems
What is the bandwidth of a first-order system with time constant τ = 0.1 seconds?
A 10 rad/s
B 100 rad/s
C 0.1 rad/s
D 1 rad/s
Correct Answer:  A. 10 rad/s
EXPLANATION

For first-order system, bandwidth ωBW = 1/τ = 1/0.1 = 10 rad/s (where -3dB occurs)

Test
Q.89 Easy Control Systems
In the root locus of a system with open-loop transfer function G(s)H(s) = K(s+2)/(s(s+1)(s+3)), how many branches exist?
A 2
B 3
C 4
D 5
Correct Answer:  B. 3
EXPLANATION

Number of root locus branches = max(number of poles, number of zeros) = max(3, 1) = 3

Test
Q.90 Easy Control Systems
Which of the following transfer functions represents a Type-2 system?
A G(s) = 5(s+1)/(s²(s+3))
B G(s) = 10/(s(s+2)(s+5))
C G(s) = 2(s+1)/(s+2)(s+4)
D G(s) = 15(s+0.5)/(s³(s+1))
Correct Answer:  A. G(s) = 5(s+1)/(s²(s+3))
EXPLANATION

Type of system is determined by the number of poles at origin. Option A has s² in denominator, making it Type-2

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