Home Subjects Electrical Engg (EEE)

Electrical Engg (EEE)

Electrical machines, power systems, circuits

321 Q 7 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 51–60 of 321
Topics in Electrical Engg (EEE)
What is the main limitation of analog instruments in automated data acquisition systems?
A Lower measurement accuracy
B Inability to provide direct digital output for computer interfacing
C Higher temperature stability
D Better frequency response
Correct Answer:  B. Inability to provide direct digital output for computer interfacing
EXPLANATION

Analog instruments cannot directly interface with digital computers; they require ADC conversion for data acquisition systems.

Test
In a potentiometer method for EMF comparison, if standard cell EMF is 1.018 V with 106.4 cm length, and unknown cell requires 107.8 cm, what is unknown EMF?
A 1.026 V
B 1.031 V
C 1.018 V
D 1.035 V
Correct Answer:  B. 1.031 V
EXPLANATION

E₂/E₁ = L₂/L₁; E₂ = (107.8/106.4) × 1.018 ≈ 1.031 V.

Test
In a LVDT (Linear Variable Differential Transformer), when the core is at null position, what happens to the output voltage?
A Maximum positive voltage
B Minimum (approximately zero)
C Maximum negative voltage
D Voltage equals excitation voltage
Correct Answer:  B. Minimum (approximately zero)
EXPLANATION

At null position in LVDT, the core is centered, and secondary voltages from both coils cancel out, resulting in zero or minimum output.

Test
A standard cell has an EMF of 1.0186 V at 20°C with temperature coefficient of -0.0004 V/°C. What will be its EMF at 25°C?
A 1.0186 V
B 1.0170 V
C 1.0180 V
D 1.0202 V
Correct Answer:  B. 1.0170 V
EXPLANATION

EMF at 25°C = 1.0186 - 0.0004 × (25-20) = 1.0186 - 0.002 = 1.0166 ≈ 1.0170 V.

Test
In a megohmmeter, what voltage is typically applied across the test terminals to measure very high resistances (> 1 MΩ)?
A 1 kV to 5 kV DC
B 230 V AC only
C 100 V DC
D 50 V AC
Correct Answer:  A. 1 kV to 5 kV DC
EXPLANATION

Megohmmeters use high DC voltages (1-5 kV) to force sufficient current through high resistances for measurable deflection.

Test
An AC bridge circuit is used to measure unknown capacitance. At balance, the product of opposite arms satisfies which condition?
A Z₁ × Z₃ = Z₂ × Z₄
B Z₁/Z₂ = Z₃/Z₄
C Z₁ × Z₄ = Z₂ × Z₃
D Z₁ + Z₃ = Z₂ + Z₄
Correct Answer:  C. Z₁ × Z₄ = Z₂ × Z₃
EXPLANATION

For AC bridges at balance condition: Z₁ × Z₄ = Z₂ × Z₃, where Z represents impedance of arms.

Test
Which method is most suitable for measuring frequency in the range of 10 Hz to 100 kHz with high accuracy in 2024-25 standards?
A Lissajous pattern method using CRO
B Digital frequency counter with microprocessor
C Resonance method with LC circuit
D Stroboscopic method
Correct Answer:  B. Digital frequency counter with microprocessor
EXPLANATION

Digital frequency counters provide accuracy of ±1 count with real-time display and are industry standard for this frequency range.

Test
A wattmeter with voltage coil rating of 300 V and current coil rating of 5 A is used to measure power in a circuit. If the actual voltage is 250 V and current is 4 A at power factor 0.8, what will be the wattmeter reading if it has full-scale deflection of 1500 W?
A 800 W
B 960 W
C 1200 W
D 1000 W
Correct Answer:  A. 800 W
EXPLANATION

Power = V × I × cos(φ) = 250 × 4 × 0.8 = 800 W. The wattmeter reading equals actual power consumed.

Test
A moving coil galvanometer has an internal resistance of 10 Ω and a full-scale deflection current of 5 mA. What shunt resistance is required to convert it into an ammeter with a range of 0-5 A?
A 0.01 Ω
B 0.02 Ω
C 0.05 Ω
D 0.1 Ω
Correct Answer:  A. 0.01 Ω
EXPLANATION

Shunt resistance Rs = (Ig × Rg)/(I - Ig) = (5×10^-3 × 10)/(5 - 5×10^-3) ≈ 0.01 Ω

Test
The null deflection method in bridge circuits is preferred over deflection method because it:
A Is faster
B Eliminates errors due to calibration and non-linearity of meter
C Requires less power
D Uses less expensive components
Correct Answer:  B. Eliminates errors due to calibration and non-linearity of meter
EXPLANATION

Null deflection (or balance) method is preferred because it doesn't depend on meter calibration or linearity. The measurement relies on the balance condition formula only.

Test
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